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riadik2000 [5.3K]
2 years ago
15

Calculate the vapor pressure (in torr) at 298 K in a solution prepared by dissolving 46.8 g of the non-volatile non-electrolye g

lucose in 117 g of methanol. The vapor pressure of methanol at 298 K is 122.7 torr. Enter your answer to 2 decimal places.
Chemistry
1 answer:
Rainbow [258]2 years ago
3 0

<u>Answer:</u> The total partial pressure of the solution is 131.37 torr.

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For glucose:</u>

Given mass of glucose = 46.8 g

Molar mass of glucose = 180 g/mol

Plugging values in equation 1:

\text{Moles of glucose}=\frac{46.8g}{180g/mol}=0.26 mol

  • <u>For methanol:</u>

Given mass of methanol = 117 g

Molar mass of methanol = 32 g/mol

Plugging values in equation 1:

\text{Moles of methanol}=\frac{117g}{32g/mol}=3.66 mol

Mole fraction is defined as the moles of a component present in the total moles of a solution. It is given by the equation:

\chi_A=\frac{n_A}{n_A+n_B} .....(2)

where n is the number of moles

Putting values in equation 2:

\chi_{methanol}=\frac{3.66}{0.26+3.66}=0.934

Raoult's law is the law used to calculate the partial pressure of the individual gases present in the mixture. The equation for Raoult's law follows:

p_A=\chi_A\times p_T .....(3)

where p_A is the partial pressure of component A in the mixture and p_T is the total partial pressure of the mixture

We are given:

p_{methanol}=122.7torr\\\chi_{methanol}=0.934

Putting values in equation 3, we get:

122.7torr=0.066\times p_T\\\\p_T=\frac{122.7torr}{0.934}=131.37torr

Hence, the total partial pressure of the solution is 131.37 torr.

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