Please help me solve this question i need help pls

A segway travels 12.5 miles every 1/2 hour. What is the unit rate of miles per hour?

belka [17]

Answer:

The answer tot he question provided is 25.

4 0

3 years ago

7x2 +11x-6/7x2 - 10x + 3

velikii [3]

Answer:

Final result :

x + 2

—————

x - 1

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant 7 • 3 = 21

Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 .

-21 + -1 = -22

-7 + -3 = -10 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3

7x2 - 7x - 3x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

7x • (x-1)

Add up the last 2 terms, pulling out common factors :

3 • (x-1)

Step-5 : Add up the four terms of step 4 :

(7x-3) • (x-1)

Which is the desired factorization

Please mark brainliest and have a great day!

3 0

3 years ago

Read 2 more answers

Make r the subject of the formula <img src="https://tex.z-dn.net/?f=v%20%3D%20%5Cpi%20%5C%3A%20h%20%7B%7D%5E%7B2%7D%28r%20-%

Vaselesa [24]

Answer:

$\boxed{r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } }$

Step-by-step explanation:

$Solve \: for \: r: \\ = > v= \pi {h}^{2}(r - \frac{h}{3} ) \\ \\ v=\pi {h}^{2}(r - \frac{h}{3} )is \: equivalent \: to \: {h}^{2}\pi(r - \frac{h}{3} ) = v: \\ = > {h}^{2}\pi(r - \frac{h}{3} ) = v \\ \\ Divide \: both \: sides \: by \: \pi {h}^{2} : \\ = > r - \frac{h}{3} = \frac{v}{\pi {h}^{2} } \\ \\ Add \: \frac{h}{3} \: to \: both \: sides: \\ = > r = \frac{h}{3} + \frac{v}{\pi {h}^{2} }$

8 0

3 years ago

Assume the competing hypotheses take the following form: H0: µ1 – µ2 = 0, HA: µ1 – µ2 ≠ 0, where µ1 is the population mean for p

DedPeter [7]

Answer:

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

Where,

$\bar x_1$ = sample meaan of population 1

$\bar x_2$ = sample mean of population 2

$n_1$ = sample size of population 1

$n_2$ = sample size of population 2

Therefore, this is the test

$t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }$

7 0

3 years ago

The range of 16,23,55,64,49

miskamm [114]

Answer: 48

Step-by-step explanation: To find the range of the data set shown here, remember that the range is the difference between the greatest number in the data set and the least number in the data set.

Greatest number → 64

Least number → 16

Now, we need to subtract 16 from 64.

64 - 16 = 48

Therefore, the range of the data set is 48.

7 0

4 years ago