Answer:
Where the electric potential is constant, the strength of the electric field is zero.
Explanation:
As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e
Eₓ = - dV / dx ----------(i)
From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.
<em>Therefore, a constant electric potential means that electric field is zero.</em>
Answer:
what was the answer
Explanation:
im taking the quiz and could use some help
<h3>
Answer:</h3>
375 N
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Explanation:</h3>
Topic tested: Newton's Law of motion
The question is testing on the application of Newton's second Law of motion.
We are given;
- Mass of the football = 5 Kg
- Initial velocity of the football, Vf = 15 m/s
- Time taken to bring the ball to rest = 0.2 s
- Final velocity, Vo = 0 m/s ( since the ball went to rest)
We are required to determine the force exerted to bring it to rest.
- According to the Newton's second law of motion the resultant force and rate of change in momentum are directly proportion.
Thus;
Force = 375 N
Hence, the force exerted on the ball by the receiver was 375 N
A conductor allows electricity to flow through it.
That's a velocity.
It has a speed and the direction of the speed.
