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2 years ago

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PLEASE HELP.

1 answer:

Irina18 [472]2 years ago

3 0

The Solar System moves through the galaxy with about a 60° angle between the galactic plane and the planetary orbital plane. The Sun appears to move up-and-down and in-and-out with respect to the rest of the galaxy as it revolves around the Milky Way and
This speed is not unusual for the stars around us and is our “milling around” speed in our suburban part of the Galaxy. In addition to the individual motions of the stars within it, the entire Galaxy is in spinning motion like an enormous pinwheel.

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Impulse: A batter applies an average force of 8000 N to a baseball for 1.1 ms. What is the magnitude of the impulse delivered to

fiasKO [112]

The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

<h3>Impulse experienced by objects</h3>

The impulse experienced by any object is equal to the change in the momentum of the object.

The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.

J = Ft

where;

F is applied force = 8000 N
t is time, = 1.1 ms

J = (8000) x (1.1 x 10⁻³)

J = 8.8 Ns

Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

Learn more about impulse here: brainly.com/question/229647

5 0

2 years ago

A Martian rover is descending a hill sloped at 30° with the horizontal. It travels with a constant velocity of 2 meters/second.

kodGreya [7K]

Vx = 2*cos30 = 1.73m's
Other words:
D = Vo*t = 1.4 * 21 = 31.5m. @ 30 Deg.
Dy = 31.5*sin30 = 15.75 m.

8 0

3 years ago

Read 2 more answers

The wave functions for states of the hydrogen atom with orbital quantum number l=0 are much simpler than for most other states,

Thepotemich [5.8K]

True. Fun fact. Hope this helps

4 0

2 years ago

8. Three grams of Bismuth-218 decay to 0.375 grams in one hour. What is the half-

Evgen [1.6K]

Answer: 0.333 h

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula</u>:

$A=A_{o}.2^{\frac{-t}{H}}$ (1)

Where:

$A=0.375 g$ is the final amount of the material

$A_{o}=3 g$ is the initial amount of the material

$t=1 h$ is the time elapsed

$H$ is the half life of the material (the quantity we are asked to find)

Knowing this, let's substitute the values and find $h$ from (1):

$0.375 g=(3 g)2^{\frac{-1h}{H}}$ (2)

$\frac{0.375 g}{3 g}=2^{\frac{-1h}{H}}$ (3)

Applying natural logarithm in both sides:

$ln(\frac{0.375 g}{3 g})=ln(2^{\frac{-1 h}{H}})$ (4)

$-2.079=-\frac{1 h}{H}ln(2)$ (5)

Clearing $H$ :

$H=\frac{-1h}{-2.079}(0.693)$ (6)

Finally:

$h=0.333 h$ This is the half-life of the Bismuth-218 isotope

4 0

3 years ago

A wave has the wavelength equal to 396 nm. what must be the frequency of this wave

Anvisha [2.4K]

This assumes that the wave has velocity c (is light).

7 0

2 years ago