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3 years ago

11

PLEASE HELP.

1 answer:

Irina18 [472]3 years ago

3 0

The Solar System moves through the galaxy with about a 60° angle between the galactic plane and the planetary orbital plane. The Sun appears to move up-and-down and in-and-out with respect to the rest of the galaxy as it revolves around the Milky Way and
This speed is not unusual for the stars around us and is our “milling around” speed in our suburban part of the Galaxy. In addition to the individual motions of the stars within it, the entire Galaxy is in spinning motion like an enormous pinwheel.

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A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The ang

olga55 [171]

Answer:

9.22 s

Explanation:

One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad

Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:

For the child: $s_c = \omega_ct = 0.233t$

For the horse: $s_h = s_0 + a_ht^2/2 = 1.57 + 0.0136t^2/2 = 1.57 + 0.0068t^2$

For the child to catch up with the horse, they must cover the same angular distance within the same time t:

$s_c = s_h$

$0.233t = 1.57 + 0.0068t^2$

$0.0068t^2 - 0.233t + 1.57 = 0$

$t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$t= \frac{0.233\pm \sqrt{(-0.233)^2 - 4*(0.0068)*(1.57)}}{2*(0.0068)}$

$t= \frac{0.233\pm0.11}{0.0136}$

t = 25.05 or t = 9.22

Since we are looking for the shortest time we will pick t = 9.22 s

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3 years ago

Two square air-filled parallel plates that are initially uncharged are separated by 1.2 mm, and each of them has an area of LaTe

RideAnS [48]

Answer:

5.5x 10^-11 C

Explanation:

Pls see attached file

7 0

3 years ago

In a tug of war between Mrs. Brenneman and Mr. Schroedl seems at a standstill. Then Mrs. Brenneman tugs hard giving a force of 4

sergiy2304 [10]

He feels a 10 N to the left force moves. Yes ,he moves.

4 0

3 years ago

WHOEVER ANSWERS RIGHT GETS BRAINLY!!

Mademuasel [1]

Answer:

I think the answer is A

Explanation:

I need this brainliest answer please

6 0

3 years ago

A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electr

Katen [24]

Answer:

ФE = 9.403W

Explanation:

In order to calculate the magnitude of the electric flux trough the sheet, you use the following formula:

$\Phi_E=\vec{A}\cdot \vec{E}=AEcos\theta$ (1)

A: area of the rectangular sheet = (0.400m)(0.600m) = 0.24m^2

E: magnitude of the electric field = 95.0N/C

θ: angle between the direction of the electric field and the normal to the surface of the sheet

You replace the values of the parameters in the equation (1):

$\Phi_E=(0.24m^2)(95.0N/m)cos(20\°)=9.304W$

The magnitude of the electric flux is trough the sheet is 9.403W

5 0

3 years ago