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Montano1993 [528]
2 years ago
11

A force of 900 N is applied to a 9kg object. How fast will it accelerate?

Physics
2 answers:
Alex_Xolod [135]2 years ago
8 0

Given :

  • Force = 900 N

  • Mass = 9kg

\\

To find :

  • Acceleration = ?

\\

We know :

\boxed{ \rm Force=Mass\times Acceleration}

<u>By using this formula we can find acceleration.</u>

\dashrightarrow \sf Force=Mass\times Acceleration \\

\\

\dashrightarrow \sf900=9\times Acceleration \\

\\

\dashrightarrow \sf900 \times  \dfrac{1}{9} =Acceleration \\

\\

\dashrightarrow \sf \cancel9 \times 100 \times  \dfrac{1}{ \cancel9} =Acceleration \\

\\

\dashrightarrow \sf \dfrac{100}{1} =Acceleration \\

\\

\dashrightarrow \sf Acceleration = \dfrac{100}{1} \\

\\

\dashrightarrow \bf Acceleration = 100\: ms^{-2}

<u>━━━━━━━━━━</u><u>━</u><u>━</u><u>━━</u><u>━</u><u>━━━━━━━━━━</u><u>━</u><u>━</u><u>━</u><u>━━━</u>

Related Concept :

Define Acceleration:

  • Acceleration is the rate by which velocity changes with respect to time

Main formula :-

a = (Vf - Vi)/t

where :-

  • Vf is final velocity
  • Vi is initial velocity
  • t is time

Define Force :

  • Force is a push or pull that changes or may tends to change an object from rest to motion or from motion to rest.

Main formula:

f = m × a

where :-

  • m is mass
  • a is acceleration
  • f is force

Define Mass :

  • The amount of matter present in body

Main formula:

m = v × d

where:-

  • m is mass
  • v is volume
  • d is density
saul85 [17]2 years ago
7 0

Answer:  15 m/s2

Explanation: I hope this helps or right because I learned this a few months ago

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Answer:

F = 41,954 N

Explanation:

given,

mass of bucket = 580 Kg

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velocity = 40 m/s

angle made = 38.0°

T cos 38° = m g..............(1)

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dividing equation (2) by (1)

tan 38^0 = \dfrac{\dfrac{mv^2}{l} + F}{mg}

tan 38^0 = \dfrac{\dfrac{580\times 40^2}{20} + F}{580 \times 9.81}

4445.36 = \dfrac{580\times 40^2}{20} + F

F = -46400 + 4445.36

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3 years ago
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Answer:

D

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While the others are either too much more or less than a humans.

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A ball is kicked horizontally at 4.6 m/s off of a cliff 13.4 m high. How far from the cliff will it land.
Mekhanik [1.2K]
<h3>Answer:</h3>

7.53 m

<h3>Explanation:</h3>

<u>We are given:</u>

Initial Horizontal Velocity of the Ball = 4.6 m/s

Initial Vertical Velocity of the Ball = 0 m/s

Height from which ball is kicked = 13.4 m

<u>Time taken by the ball to reach the ground:</u>

The ball has an initial vertical velocity of 0 m/s

it also has a downward acceleration of 10 m/s² due to gravity

<u>Solving for the time taken:</u>

s = ut + 1/2(at²)                 [second equation of motion]

replacing the values

13.4 = (0)(t) + 1/2 (10)(t²)

13.4 = 5t²

t² = 13.4/5                  [dividing both sides by 5]

t² = 2.68

t = 1.637 seconds     [taking the square root of both sides]

<u>Horizontal distance covered by the ball:</u>

Since there are no horizontal opposing forces on the ball,

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We calculated that the ball will hit the ground in 1.637 seconds

<u>Distance covered:</u>

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s = ut                                            [since a = 0m/s² in the horizontal plane]

replacing the values

s = 4.6 * 1.637

s = 7.53 m

Hence, the ball landed 7.53 m from the cliff

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