Use a let statement
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
-323 -323
x^2 + 2x -323 = 0
third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19
x = -17
hope this help
It's factorable when c ∈ {5,8,9}
