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True [87]
3 years ago
5

Given that ABCD is a rhombus, what is the value of x?

Mathematics
1 answer:
stealth61 [152]3 years ago
4 0

Answer:

Diagonals of a rhombus intersect at right angles

Therefore, \angle AOD=90

Now,in\: \bigtriangleup AOD

\angle OAD+\angle AOD+\angle ADO=180

x+90+3x+12=180 \leftarrow [combing \: like\: terms]

4x+102=180\\-102   \: -102 \leftarrow [subtracting \:102 ]

\frac{4x}{4} =\frac{78}{4} \leftarrow [dividing \: by\: 4]

x=19.5 \Longleftarrow

<u>OAmalOHopeO</u>

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