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alekssr [168]
3 years ago
10

You need to figure out how high it is from the 3rd floor of Keck science building to the ground. You know that the distance from

the ground to the 2nd floor is 5m. Your friend drops a ball from rest from the 3 rd floor and you start to time the ball when it passes by you at the 2nd floor. You stop the timer when the ball hits the ground. The time recorded is 0.58 seconds.
Physics
1 answer:
Tcecarenko [31]3 years ago
4 0

Answer:1.624 m

Explanation:

Given

height of 2nd floor =5 m

time recorded is 0.58 sec

Let h be the height of third floor above 2 nd floor

h=ut+\frac{at^2}{2}

here u=0

t=time taken to cover height h

h=\frac{gt^2}{2}   ----------1

Now time taken to complete whole building length

h+5=\frac{g(t+0.58)^2}{2}  ----------2

Subtract 1 form 2

5=\frac{g(2t+0.58)(0.58)}{2}

Taking gravity g=1 m/s^2

1=(2t+0.58)(0.58)

t=0.57 s

Substitute the value of t in 1

h=1.624 m

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Explanation:

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d2 = 1 m north west

d3 = 1 m vertically down

Write the displacements in vector form

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The resultant displacement is given by

\overrightarrow{d}=\overrightarrow{d_{1}}+ \overrightarrow{d_{2}} +\overrightarrow{d_{3}}

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The magnitude of displacement is given by

d =

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3 years ago
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Hope this helps :)

8 0
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Without doing any math, it can be seen from the equation that work is directly proportional to the force applied and the distance it travels.  The homerun hit both traveled more distance and had a grater force applied to it in order to achieve this distance (assuming both baseballs weighed the same).  Based on this reasoning, it is valid to conclude that the baseball which was a homerun was the hit that accomplished more work.

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