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MrRissso [65]
3 years ago
9

Help asap! 30 pts and brainliest!

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

July

Step-by-step explanation:

Took terst

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There are 125 skittles in a bag. This consists of 35 red, 25 yellow, 20 purple, 15 green and 30 orange skittles. Find the percen
tino4ka555 [31]

Answer:

red=28℅,yellow =20℅, purple =16℅, green =12℅, orange=24℅

Step-by-step explanation:

total skittles =125

now,

To find the percentage of each skittles,

red =35 (<u>3</u><u>5</u><u> </u>×100) =28 ℅

125

u can find each ℅ by same method.

hope it help u.

3 0
3 years ago
ANSWER THE 2 QUESTION IN 1 MINUTE AND YOU WILL BE THE BRAINLIEST! QUICK QUICK PLEASE!
Oksi-84 [34.3K]

Answer:

1. 54

2. 5

Step-by-step explanation:

1. 18 x 3 = 54

2. 90/18 = 5

4 0
4 years ago
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Points (3,1) and (1,4) lie on line k. What is the slope of the line that is perpendicular to k?
denis-greek [22]
First we need to find the slope of line k.  Using the slope formula, we fill in accordingly: m= \frac{4-1}{1-3}.  The slope is -3/2.  The slope of a line that is perpendicular to line k will have the opposite sign (so, positive) and will be the reciprocal of the line k's slope (so, 2/3).  You could also say, more "mathematically legal", that the product of the slopes of perpendicular lines is -1, but it's easier to just say that they are opposite reciprocals.  The slope you're looking for is 2/3.  Choice 3 above.
6 0
3 years ago
Which is the correct way to evaluate f(15) for the function f(x)=2(x+3)?
Thepotemich [5.8K]

Answer:

the first option

Step-by-step explanation:

Start by substituting 15 for x. Then, simplify to get f(15)=36.

cuz

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f(15)=2(15+3)

= 2×18=36

gimme brainliest plz

3 0
3 years ago
Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)
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So, a line parallel to <span>y - 5x = 10, will have the same slope as that equation, so what is that slope anyway?  let's solve for "y".

</span>\bf y-5x=10\implies y=5x+10\implies y=\stackrel{slope}{5}x\stackrel{y-intercept}{+10}
<span>
alrite, so the slope is 5 then, well, then the parallel line will have the same slope.

so, we're really looking for the equation of a line whose slope is 5 and runs through 3,10.


</span>\bf \begin{array}{lllll}&#10;&x_1&y_1\\&#10;%   (a,b)&#10;&({{ 3}}\quad ,&{{ 10}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies 5&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-10=5(x-3)&#10;\\\\\\&#10;y-10=5x-15\implies y=5x-5<span>
</span>
6 0
3 years ago
Read 2 more answers
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