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SVEN [57.7K]
3 years ago
13

Which expression is a perfect cube?

Mathematics
2 answers:
Alex17521 [72]3 years ago
5 0

Answer:

Only y^{24} is a perfect cube.

Step-by-step explanation:

x^{8} is not a perfect cube because 8 is not a multiple of 3.

Now, y^{24} is a perfect cube since 24 is a multiple of 3.  

So, y^{24} can be expressed as  

y^{24} =y^{8+8+8}= y^{8} \times y^{8} \times y^{8}= (y^{8}) ^{3}  

Again, m^{28} is not a perfect cube as 28 is not a multiple of 3.

And also s^{64} is not a perfect cube as 64 is not a multiple of 3.  

Therefore, only y^{24} is a perfect cube. (Answer)

Ainat [17]3 years ago
5 0

Answer:

Option B.

Step-by-step explanation:

We need to find the expression that is a perfect cube.

First expression is x^8. The degree of x is 8 which is not divisible by 3. So, x^8 is not a perfect cube.

Second expression is y^{24}. The degree of y is 24 which is divisible by 3.

y^{24}=y^{8\times 3}=(y^8)^3        [\because (x^m)^n=x^{mn}]

So, y^{24} is a perfect cube.

Third expression is m^{28}. The degree of m is 28 which is not divisible by 3. So, m^{28} is not a perfect cube.

Fourth expression is s^{64}. The degree of s is 64 which is not divisible by 3. So, s^{64} is not a perfect cube.

Therefore, the correct option is B.

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