Please help :( I’ve been on this fit awhile

The base of a rectangular fish tank measures 18 inches long by 10 inches wide. If it is filled with 1,080 cubic

Oxana [17]

Answer:

Volume = length x width x height

V = 18 x 8 x 12 = 1728 cm3 = 1728 ml = 1.729 liters

Step-by-step explanation:

5 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER. Find the values of

soldier1979 [14.2K]

Step-by-step explanation:

I am not sure this is a square.

this could be a rectangle.

to be safe, I am following that path.

in a rectangle opposite sides are of equal length.

that means

y - 1 = 2y - 7

y = 2y - 6

0 = y - 6

y = 6

3x - 4 = 3y - 13

3x - 4 = 3×6 - 13

3x - 4 = 18 - 13 = 5

3x = 9

x = 3

as it turns out, it is a square, so we could have used every side expression to be equal with every other side expression, but better safe than sorry ...

5 0

2 years ago

Seth sells candles for $14.35 each. Last week, he sold 21 candles. Seth pays $2.40 for materials for every 3 candles. How much d

Zigmanuir [339]

Answer:

$284.55

Step-by-step explanation:

total of sold candles:$14.35 × 21 = $301.35

total for materials : 21÷3 = 7

=7×$2.40

=$16.8

net earn; $301.35-$16.8 =$284.55

6 0

2 years ago

the reptile house at the zoo has 245 reptiles.each habitats hold s 5 reptiles how many habitats are there

Usimov [2.4K]

49 habitats are at the zoo because 245 divided by 5 is 49! (: (: (: hope I helped

6 0

3 years ago

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