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Ugo [173]
1 year ago
5

2.5(10x - 16) = 5 What decimal represents the solution to the equation?

Mathematics
1 answer:
Pavlova-9 [17]1 year ago
4 0

2.5(10x - 16) = 5

2.5 is multiplying on the left, then it will divide on the right

10x - 16 = 5/2.5

10x - 16 = 2

16 is subtracting on the left, then it will add on the right

10x = 2 + 16

10x = 18

10 is multiplying on the left, then it will divide on the right

x = 18/10

x = 1.8

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Use the properties of exponents to rewrite the expression.<br> (-3yz)(-3yz)(-3yz)(-3yz)
Lera25 [3.4K]

Answer:

Answer is 81y^4z^4

Step-by-step explanation:

The expression is (-3yz) (-3yz) (-3yz) (-3yz).

Since all the four terms have power 1:

(-3yz)^1 (-3yz)^1 (-3yz)^1 (-3yz)^1

We know that we can add the powers if the terms have same base

So,

=(-3yz)^1+1+1+1

=(-3yz)^4

=(-3)^4(y)^4(z)^4.

If the power is an even number than the negative sign changes into positive sign.

=3^4y^4z^4

=81y^4z^4

Thus the answer is 81y^4z^4....

3 0
3 years ago
Write a rule for the linear function with the following description: the graph contains the points (3,-2) and (3,0),
Maslowich

Answer:

x - 3 = 0

Step-by-step explanation:

You can realise it plotting the points.

Or you can use : ( x - x1 ) / ( y - y1 ) = ( x1 - x2 ) / ( y1 - y2 )

where ( x1 , y1 ) and ( x2 , y2 ) are the given points.

3 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
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Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

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If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

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3 years ago
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Answer:

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3 years ago
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Answer:

Im thinking it is 50

Step-by-step explanation:

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