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Ugo [173]
1 year ago
5

2.5(10x - 16) = 5 What decimal represents the solution to the equation?

Mathematics
1 answer:
Pavlova-9 [17]1 year ago
4 0

2.5(10x - 16) = 5

2.5 is multiplying on the left, then it will divide on the right

10x - 16 = 5/2.5

10x - 16 = 2

16 is subtracting on the left, then it will add on the right

10x = 2 + 16

10x = 18

10 is multiplying on the left, then it will divide on the right

x = 18/10

x = 1.8

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Answer:

Please check the explanation.

Step-by-step explanation:

<u>Determining the length of BC</u>

From the diagram, it is clear that

  • The point B is located at (-8, 10) and point C is located at (8, 10)

Since points A and C are located on a horizontal straight line. Thus, the length of BC can be determined by counting the x-axis units from reaching x = -8 to x = 8. i.e. 8-(-8) = 8+8 = 16

Thus, the length of BC = 16 units

<u>Determining the length of CD</u>

Given

  • C (8, 10)
  • D (2, -2)

The distance between C(8, 10) and D(2, -2)

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

CD=\sqrt{\left(2-8\right)^2+\left(-2-10\right)^2}

      =\sqrt{6^2+12^2}

      =\sqrt{36+144}

      =\sqrt{180}

      =\sqrt{36\times 5}

      =6\sqrt{5}

Thus, the length of CD =6\sqrt{5} units

<u>Determining the length of ED</u>

Given

  • E (-8, -4)
  • D (2, -2)

The distance between E(-8, -4) and D(2, -2)

ED=\sqrt{\left(2-\left(-8\right)\right)^2+\left(-2-\left(-4\right)\right)^2}

      =\sqrt{10^2+2^2}

      =\sqrt{100+4}

      =\sqrt{104}

       =\sqrt{26\times \:4}

        =2\sqrt{26}

Thus, the length of ED =2\sqrt{26} units

<u>Determining the length of EB</u>

From the diagram, it is clear that

  • The point E is located at (-8, -4) and the point B is located at (-8, 10)

Since points E and B are located on a vertical straight line. Thus, the length of EB can be determined by counting the y-axis units from reaching y = -4 to y = 10. i.e. 10-(-4) = 10+4 = 14

Thus, the length of EB = 14 units

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