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givi [52]
3 years ago
12

List all subsets of the following set [1]?

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0
ANSWER

{},{1}

EXPLANATION

The given set has one element. So it has 2^1=2 subsets.

These are,

{} and {1}.

That is, the null set and the set itself.

Remember that, the null set is a subset of every set and every set is a subset of itself.
Luda [366]3 years ago
3 0

Answer:

{ } and {1}

Step-by-step explanation:

Let as consider the given set

S=\{1\}

We need to find tall subsets of the given set.

Number of subsets of a set = 2^n

where, n is the number of elements in that set.

In the given set the number of elements = 1.

Number of subsets of given set = 2^1=2

So, the number of subsets of given set is 2.

If all elements of set A are included in set B, then A is subset of set B.

A\subseteq B

Empty set or ∅ is the subset of all sets and each set is the subset of itself. It means

\{ \}\subseteq \{1\}

\{ 1\}\subseteq \{1\}

Therefore, subsets of given set are { } and {1}.

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<u>Construction</u><u> </u><u>-</u>

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Now , we can clearly see that AECD is a parallelogram !

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area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

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