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givi [52]
3 years ago
12

List all subsets of the following set [1]?

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0
ANSWER

{},{1}

EXPLANATION

The given set has one element. So it has 2^1=2 subsets.

These are,

{} and {1}.

That is, the null set and the set itself.

Remember that, the null set is a subset of every set and every set is a subset of itself.
Luda [366]3 years ago
3 0

Answer:

{ } and {1}

Step-by-step explanation:

Let as consider the given set

S=\{1\}

We need to find tall subsets of the given set.

Number of subsets of a set = 2^n

where, n is the number of elements in that set.

In the given set the number of elements = 1.

Number of subsets of given set = 2^1=2

So, the number of subsets of given set is 2.

If all elements of set A are included in set B, then A is subset of set B.

A\subseteq B

Empty set or ∅ is the subset of all sets and each set is the subset of itself. It means

\{ \}\subseteq \{1\}

\{ 1\}\subseteq \{1\}

Therefore, subsets of given set are { } and {1}.

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Mrac [35]

Answer:

g(x) = 4x + 4

Step-by-step explanation:

The given function is f(x)=x.

If we stretch vertically by a factor of 4 and a translation of 4 units up then the new function becomes

g(x) = 4f(x) + 4

But f(x)=x

We substitute to obtain the equation of g(x) as

g(x) = 4x + 4

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3 years ago
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8_murik_8 [283]
Sum of 5 times z and 4 divided by two is 7.

\frac{5z+4}{2} = 7
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1. Simplify - 5b • 4 + 6a - 4a.4-45 + 5-4.-13a - 1
NISA [10]

answer: -8.6a-2b-45

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3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
What are the main properties of a rectangle <br> Use rectangle (BCDE) to help you .
OleMash [197]

Answer:

it must be number 1

I am sure about parallel side and 4 right angles

6 0
3 years ago
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