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maw [93]
3 years ago
6

A tank contains seven liters of 10% alcohol solution. how many liters of 6% alcohol should be added to have 8% alcohol solution?

Mathematics
1 answer:
kow [346]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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posledela

Answer:

MOE_{95} = 1.192\cdot MOE_{90}

Step-by-step explanation:

The margin of error is computed using the formula:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical of <em>z</em> for 95% confidence level and 90% confidence level are:

z_{0.05/2}=z_{0.025}=1.96\\\\z_{0.10/2}=z_{0.05}=1.645

*Use a <em>z</em>-table.

The sample size is n = 44.

Compare the MOE for 95% confidence level and 90% confidence level as follows:

\frac{MOE_{95}}{MOE_{90}}=\frac{1.96\times (15/\sqrt{44})}{1.645\times (15/\sqrt{44})}

\frac{MOE_{95}}{MOE_{90}}=\frac{1.96}{1.645}\\\\\frac{MOE_{95}}{MOE_{90}}=1.192\\\\MOE_{95} = 1.192\cdot MOE_{90}

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