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Feliz [49]
3 years ago
13

“Find the missing side length of the right triangle, round to the nearest hundredth. EXPLAIN HOW YOU GOT YOUR ANSWER AND WHICH T

RIGONOMETRIC RATIO YOU USED.”

Mathematics
1 answer:
katrin2010 [14]3 years ago
7 0

Answer:

X=21.21

Step-by-step explanation:

Cos(45)=15\x

0.707=15\x

15\0.707 =x

X= 21.21

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1. Identify the parallel lines.
saul85 [17]

Answer:

1. The parallel lines are m and n

2. The transversal is line t.

3. 8 angles are formed by the transversal.

4. Angles 7 and 5, 1 and 3, 2 and 4, 6 and 8, 6 and 2, 7 and 3, 1 and 5, 4 and 8, 3 and 5, 2 and 8, 4 and 6, and 1 and 7.

5. If m<5 is 110°, then m<1 is also 110°

Hope this helps

4 0
3 years ago
Shryia read a 480-page-long book cover to cover in a single session, at a constant rate. After reading for 1.5 hours, she had 40
svet-max [94.6K]

Answer:

The required equation is P(t) = -52t + 480

Step-by-step explanation:

Consider the provided information.

Let P represent the number of pages left to read after t hours.

Shryia read a 480-page-long book cover to cover in a single session, at a constant rate. After reading for 1.5 hours, she had 402 pages left to read.

Total number of page Shryia read in 1.5 hours is:

480-402 = 78

It is given that the rate is constant i.e 1.5 hours,

Therefore, she read 78 pages in 1.5 hours.

She can read \frac{78}{1.5} = 52 page per hour

The required equation is:

P(t) = -52t + 480

Where t represents the number of hours.

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP
BigorU [14]

Answer:

\frac{100}{274} or \frac{50}{173} are not boxcars

Step-by-step explanation:

4 0
3 years ago
use the definition of countinuity to find the value of k so that the function is continuous for all real numbers
liubo4ka [24]

First of all, recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

So if <em>x</em> < 4, then <em>x</em> - 4 < 0, so |<em>x</em> - 4| = -(<em>x</em> - 4), and the first case in <em>h(x)</em> reduces to

\dfrac{|x-4|}{x-4}=\dfrac{-(x-4)}{x-4} = -1

Next, in order for <em>h(x)</em> to be continuous at <em>x</em> = 4, the limits from either side of <em>x</em> = 4 must be equal and have the same value as <em>h(x)</em> at <em>x</em> = 4. From the given definition of <em>h(x)</em>, we have

h(4) = 5k-4\cdot4 = 5k-16

Compute the one-sided limits:

• From the left:

\displaystyle \lim_{x\to4^-}h(x) = \lim_{x\to4}\frac{|x-4|}{x-4} = \lim_{x\to4}(-1) = -1

• From the right:

\displaystyle \lim_{x\to4^+}h(x) = \lim_{x\to4}(5k-4x) = 5k-16

If the limits are to be equal, then

-1 = 5<em>k</em> - 16

Solve for <em>k</em> :

-1 = 5<em>k</em> - 16

15 = 5<em>k</em>

<em>k</em> = 3

3 0
2 years ago
Solve the system of equations.<br> y = 6x<br> y= x^2 +5
kirza4 [7]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
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