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Gennadij [26K]
2 years ago
7

The quotient of a number m and -3.2 is 15.

Mathematics
1 answer:
Montano1993 [528]2 years ago
3 0

Answer: m/-3.2 =15

Step-by-step explanation: quotient means you  going need to divide .is 15 means =15.

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The constraints of a problem are listed below. What are the vertices of the feasible region?<br>​
Mamont248 [21]

Answer:

Option 4 : (0.\frac{3}{2} ) \ , \ (0,2) \ , \ (6,0) \ , \ (\frac{9}{4} ,0)

Step-by-step explanation:

<u>See the attached figure:</u>

To find the vertices of the feasible region, we need to graph the constraints, then find the area included by them, then calculate the vertices which is the intersection between each two of them.

As shown, the shaded area represents the solution of the constraints

So, the vertices of the feasible region are:

(0.\frac{3}{2} ) \ , \ (0,2) \ , \ (6,0) \ , \ (\frac{9}{4} ,0)

8 0
3 years ago
Read 2 more answers
Which quadratic inequality does the graph below represent?
sergejj [24]

Answer:

y< or equal to x^2-3.

I hope it helps.

4 0
2 years ago
9,513 rounded to the nearest thousand
zhenek [66]
9513 rounded to the nearest thousandth is 10,000.

I hope that helped! :>
4 0
3 years ago
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A player tosses a die 6 times.If gets a number 6 Atleast two times he wins 2 dollars ,otherwise he looses 1 dollar.. Find the ex
swat32

Answer:

E(x)=-0.2101

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x_1*p(x_1)+x_2*p(x_2)

Where x_1 and x_2 are the values that the variable can take and p(x_1) and p(x_2) are their respective probabilities.

So, a player can win 2 dollars or looses 1 dollar, it means that x_1 is equal to 2 and x_2 is equal to -1.

Then, we need to calculated the probability that the player win 2 dollars and the probability that the player loses 1 dollar.

If there are n identical and independent events with a probability p of success and a probability (1-p) of fail, the probability that a events from the n are success are equal to:

P(a)=nCa*p^a*(1-p)^{n-a}

Where nCa=\frac{n!}{a!(n-a)!}

So, in this case, n is number of times that the player tosses a die and p is the probability to get a 6. n is equal to 6 and p is equal to 1/6.

Therefore, the probability  p(x_1) that a player get at least two times number 6, is calculated as:

p(x_1)=P(x\geq2)=1-P(0)-P(1) \\\\P(0) =6C0*(1/6)^{0}*(5/6)^{6}=0.3349\\P(1)=6C1*(1/6)^{1}*(5/6)^{5}=0.4018\\\\p(x_1)=1-0.3349-0.4018\\p(x_1)=0.2633

On the other hand, the probability p(x_2) that a player don't get  at least two times number 6, is calculated as:

p(x_2)=1-p(x_1)=1-0.2633=0.7367

Finally, the expected value of the amount that the player wins is:

E(x)=x_1*p(x_1)+x_2*p(x_2)\\E(x)=2*(0.2633)+ (-1)*0.7367\\E(x)=-0.2101

It means that he can expect to loses 0.2101 dollars.

3 0
3 years ago
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Graph y=3 to the power of x
tino4ka555 [31]
Create a T chart and put 1,2,3 (x's)on one side and then solve your y's which in this instance are super easy because they all equal 3 so your points will be (1,3) (2,3) (3,3) and then just put those on your graph.
5 0
3 years ago
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