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The distance AD is found by Pythagoras theorem, with
AD=sqrt(BC^2+(AB-DC)^2)=sqrt(21^2+2^2)=sqrt(441+4)=sqrt(445)
=
21.095 (to the third decimal place)
Answer:
Step-by-step explanation:
I made a table with a pretend number of years of teaching by picking a somewhat random number to start
"Clark has less seniority than Cornwall but more than Prendergast:" I picked 3 for Clark 4 for Cornwall, and 2 for Prendergast, to start.
"Prendergast has more than Brown but less than Alexander:" I see I'm running out of easy numbers here. "Prendergast has more than Brown" means give Brown 1 year but this new teacher, Alexander needs a number between Clark and Prendergast. To make room, I increased Clark and Cornwall by 1 and finished the remainder in the "Final Years" column:
<u>Teacher </u> <u>Years</u> <u> Final Years</u>
Clark 3 4
Cornwall 4 5
Prendergast 2
Brown 1
Alexander 3
The highest seniority teacher, Cornwall, is smart and refuses the job. That leaves Clark, at number 2 seniority, to become the new supervisor.
Answer:
Step-by-step explanation:
Um
Answer:
Step-by-step explanation:
Answer:
you would be dividing so it will be n over 8
Step-by-step explanation:
n/8...
hope this helped?
