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3 years ago

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The plum pudding model of the atom states that

2 answers:

seropon [69]3 years ago

8 0

Answer:

According to this model, the atom is a sphere of positive charge, and negatively charged electrons are embedded in it to balance the total positive charge.

Explanation:

Hope this helps you

labwork [276]3 years ago

8 0

Answer:

<em>The plum pudding model of the atom states that</em><em> </em><em><u> had negatively-charged electrons embedded within a positively-charged "soup." </u></em>

Explanation:

<u>Thomson's plum pudding model of the atom</u><u> had negatively-charged electrons embedded within a positively-charged "soup." </u><u>Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.</u>

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Discuss the factors that are used to determine power.

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<span>The factors that are used to determine power are:
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2 years ago

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3 years ago

A baseball is moving at a speed of 2.2m/s when it strikes the catchers glove. The paddding of the glove is compressed by 24mm be

Andre45 [30]

Average acceleration of the baseball: $-101 m/s^2$

Explanation:

Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:

$v^2-u^2=2as$

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the displacement of the object

For the baseball in this problem, we have:

u = 2.2 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

s = 24 mm = 0.024 m is the displacement of the ball while decelerating

Therefore, we can solve for a to find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{0-2.2^2}{2(0.024)}=-101 m/s^2$

where the negative sign means the baseball is slowing down.

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3 years ago

At a certain location, Earth has a magnetic field of 0.60 ✕ 10−4 T, pointing 75° below the horizontal in a north-south plane. A

saveliy_v [14]

Answer with Explanation:

We are given that

Magnetic field,B= $0.6\times 10^{-4} T$

$\theta=75^{\circ}$

Length of wire,l=15 m

Current,I=19 A

a.We have to find the magnitude of magnetic force and direction of magnetic force.

Magnetic force,F= $IBlsin\theta$

Using the formula

$F=0.6\times 10^{-4}\times 15\times 19sin75$

$F=16.5\times 10^{-3} N$

Direction= $tan\theta=cot(90-75)=tan15^{\circ}$

$\theta=15^{\circ}$

15 degree above the horizontal in the northward direction.

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3 years ago