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bulgar [2K]
3 years ago
8

What is the speed acquired by a freely falling object 4 seconds after being dropped from a rest position? Use units of meter per

second (m/s) and assume acceleration from gravity is 10 m/s2.
Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

speed = 40 m/s

Explanation:

Since the object is dropped, V0y = 0.

Vy = V0y - gt

= -(10 m/s^2)(4 s)

= -40 m/s

This means that its velocity is 40 m/s downwards. Its speed is simply 40 m/s.

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What is the electric field due to a point charge of 20uC at a distance of 1 meter away from it?
Anettt [7]

The electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \frac{N}{C}.

First, you have to know that the space surrounding a load suffers some kind of disturbance, since a load located in that space will suffer a force. The disturbance that this charge creates around it is called an electric field.

In other words, an electric field exists in a certain region of space if, when introducing a charge called witness charge or test charge, it undergoes the action of an electric force.

The electric field E created by the point charge q at any point P, located at a distance r, is defined as:

E=K\frac{q}{r^{2} }

where K is the constant of Coulomb's law.

In this case, you know:

  • K= 9×10⁹\frac{Nm^{2} }{C^{2} }
  • q= 20 uC=20×10⁻⁶ C
  • r= 1 m

Replacing in the definition of electric field:

E=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{20x10^{-6} C}{(1 m)^{2} }

Solving:

<u><em>E=180000 </em></u>\frac{N}{C}<u><em /></u>

Finally, the electric field due to a point charge of 20uC at a distance of 1 meter away from it is 180000 \frac{N}{C}.

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Answer:

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If there are two bulbs in series, and each bulb has

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