As we know that electrostatic force between two charges is given as

here we know that electrostatic repulsion force is balanced by the gravitational force between them
so here force of attraction due to gravitation is given as

here we can assume that both will have equal charge of magnitude "q"
now we have



now we have

Answer:
15.7 m
Explanation:
The range (horizontal distance) of the projectile is determined only by its horizontal motion.
The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:

where
v = 12.0 m/s is the initial velocity
is the angle between the direction of v and the horizontal
Substituting,

We know that the projectile hits the ground in a time of
t = 2.08 s
so the horizontal distance covered is

R = 18 ohms
Explanation:
Given:
V = 36 volts
I = 2.0 A
R = ?
Use Ohm's law to solve for the resistance:
V = IR
or
R = V/I
= (36 volts)/(2.0 A)
= 18 ohms