Question

1 point What is the slope of a line perpendicular to 3x + 4y = -2?

Answer 1

Answer:

4/3

Step-by-step explanation:

In slope-intercept form $y=mx+b$, $m$ represents the slope of the line.

Let's write $3x+4y=-2$ in slope-intercept form by isolating $y$:

$3x+4y=-2,\\4y=-3x-2,\\y=-\frac{3}{4}x-\frac{1}{2}$

Therefore, the slope of this line is $\frac{-3}{4}$. To find the slope of a line perpendicular to it, multiply the reciprocal of the slope by -1 (take the negative reciprocal).

Therefore, the slope of a line perpendicular to $3x+4y=-2$ is:

$m_{perp}=-(-\frac{4}{3})=\boxed{\frac{4}{3}}$

Answer 2

Answer:

4/3

Given equation :-

• 3x + 4y = -2
• 4y = -3x - 2
• y = (-3x - 2)/4
• y = -3/4 x - 1/2

Slope :-

• m = -3/4

Slope of perpendicular line :-

• m' = -(1/m )
• m' = -( 1 ÷ -3/4 )
• m' = -1 * -4/3
• m = 4/3