All categories

3 years ago

Group 18 noble gases are relatively inert because *

Chemistry

1 answer:

choli [55]3 years ago

3 0

Answer:I believe its A. There noble gasses so there happy with there electron count!

Explanation:

You might be interested in

In the 1700's, a French chemist named Antoine Lavoisier

Dominik [7]

The Law of Conservation of Mass

4 0

3 years ago

Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is S2(g)+C(s)↽−−⇀CS2(g)????c=9.40 at 900 K Ho

Maru [420]

Answer : The mass of $CS_2$ is, 555.028 grams

Explanation :

First er have to calculate the concentration of $S_2$ .

$\text{Concentration of }S_2=\frac{\text{Moles of }S_2}{\text{Volume of solution}}=\frac{8.08mole}{5.35L}=1.51mole/L$

Now we have to calculate the concentration of $CS_2$ .

The given balanced chemical reaction is,

$S_2(g)+C(s)\rightleftharpoons CS_2(g)$

Initial conc. 1.51 0 0

At eqm. conc. (1.51-x) (x) (x)

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CS_2]}{[S_2]}$

Now put all the given values in this expression, we get :

$9.40=\frac{x}{(1.51-x)}$

By solving the term 'x', we get :

x = 1.365 M

Concentration of $CS_2$ = x M = 1.365 M

Now we have to calculate the moles of $CS_2$ .

$\text{Moles of }CS_2=\text{Concentration of }CS_2}\times \text{Volume of solution}=1.365mole/L\times 5.35L=7.303mole$

Now we have to calculate the mass of $CS_2$ .

Molar mass of $CS_2$ = 76 g/mole

$\text{Mass of }CS_2=\text{Moles of }CS_2}\times \text{molar mass of }CS_2}=7.303mole\times 76g/mole=555.028g$

Therefore, the mass of $CS_2$ is, 555.028 grams

3 0

4 years ago

Using water and the reagents provided in the lab, create two solutions such that when you mix equal amounts together, the result

Bingel [31]

Here’s one of many possibilities.

We MUST know the heat of reaction, ΔH, before we start .

Let’s assume that the reaction is

A + B → Products; ΔH = -80 kJ·mol⁻¹

Let’s assume that you want to get 100 mL of solution that warms from 25 °C to 50 °C.

For the solution

q = mcΔT = 100 g × 4.184 J·K⁻¹mol⁻¹ × 25 K = 10 460 J = 10.46 kJ

The reaction must supply 10.46 kJ.

For the reaction

nΔH = 10.46 kJ

n = 10.46 kJ/80 kJ = 0.131 mol

So, you need 0.131 mol A and 0.131 mol B.

Assume you are using the 3 mol·L⁻¹ solutions.

Then

V = 0.131 mol × (1 L/3 mol) = 0.0436 L = 46.6 mL

You need 46.6 mL of 3 mol·L⁻¹ A + 46.6 mL of 3 mol·L⁻¹ B.

Add 3.4 mL distilled water to 46.6 mL of 3 mol·L⁻¹ A to make 50 mL of A.

Add 3.4 mL distilled water to 46.6 mL of 3 mol·L⁻¹ B to make 50 mL of B.

Mix the two solutions, and you will have 100 mL of a solution at 50 °C .

8 0

4 years ago

Which type of change occurs when electrons form a bond between two atoms?

Nataly [62]

B is the answer. hope this helps

8 0

4 years ago

Write the formula: carbon hexabromide

KATRIN_1 [288]

Answer: C2Br6

Explanation:

8 0

3 years ago