To find the missing width/length for the perimeter of a rectangle:
You multiply the found length/width, in this case, the length, by 2. Since there are 2 of the same sides of a rectangle.
6*2 = 12
Now, you have to subtract the perimeter, 26, from the product.
36 - 12 = 24.
You have to divide the difference by 2 because 24 is the 2 missing sides put together.
24/2 = 12
So, the missing width is 12 feet.
From,
Loafly
The answer is A) x = 9
We know this because every four sided figure has angles that measure up to 360. So we can subtract all of the angles and then use the remaining angle to solve the problem.
360 - 90 - 90 - 99 = 81.
So with the remaining angle being 81, we can solve for x.
x^2 = 81
x = +/-9
Since +9 is the only answer that makes sense in this case, x = 9.
Answer:
Mean = average. Add up all the numbers, divide it by the number of numbers and there you go.
Median is the middlest number, For example 11, 12, 13, 14, 15. The median would be 13.
Mode is the most often number. For example 11, 11, 12, 13, 14, 14, 14, 15. The answer would be 14.
range is subtracting the lowest number from the highest number. For example, 11, 12, 13, 14, 15. The answer would be 4.
Answer
1/xy
Reduce the fraction with 4
Simplify that expression
Simplify it again
Use community property to reorder the terms
And you get 1/xy
The only way to write 42 as the product of primes (except to change the order of the factors) is 2 × 3 × 7. We call 2 × 3 × 7 the prime factorization of 42. It turns out that every counting number (natural number) has a unique prime factorization, different from any other counting number. This fact is called the Fundamental Theorem of Arithmetic. Fundamental theorem of arithmetic
In order to maintain this property of unique prime factorizations, it is necessary that the number one, 1, be categorized as neither prime nor composite. Otherwise a prime factorization could have any number of factors of 1, and the factorization would no longer be unique.
Prime factorizations can help us with divisibility, simplifying fractions, and finding common denominators for fractions.