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MrRa [10]
3 years ago
12

I need answer for this​

Mathematics
2 answers:
Gnesinka [82]3 years ago
4 0

Break down each expression and then look at the common terms...

\tt \: 9 = 1×3×3 \\  \sf \: 5 {b}^{3}  = 1 \times 5\times b \times b \times b

  • Looking at the common factors

➪ <em>The common factor is 1, Therefore their GCF is 1...</em>

Paraphin [41]3 years ago
3 0
  • 9=3×3×3×1
  • 5b^3=5×b^3×1

Greatest common factor is 1

Note

  • GCF stands for Greatest common factor
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Polar and cartesian equation<h2>Initial explanation</h2>

Let's analyze the relation between r and x and y:

We have that between the indicated value of r (of the polar coordinates) and x and y (of the cartesian coordinates) there is a relation because they form a triangle. If r changes, then the value of x and y will change.

<h2>STEP 1: given equation</h2>

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\begin{gathered} r=2secØ \\ \downarrow \\ \frac{r}{2}=secØ \end{gathered}<h2>STEP 2: secØ equation</h2>

Observing the image of the initial explanation we have a right triangle, we know that the equation of

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adjacent side = x

then,

\begin{gathered} \sec Ø=\frac{\text{hypotenuse}}{\text{adjacent side}}=\frac{r}{x} \\ \sec Ø=\frac{r}{x} \end{gathered}<h2>STEP 3: comparison between given equation and secØ equation</h2>

Then, we have that:

\begin{gathered} \sec Ø=\frac{r}{x} \\ \sec Ø=\frac{r}{2} \end{gathered}

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\begin{gathered} \frac{r}{x}=\sec Ø=\frac{r}{2} \\ \downarrow \\ \frac{r}{x}=\frac{r}{2} \end{gathered}

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