As the greater force of tension (by 81N) is exerted by the team on the right the rope will move to the right.
Answer:
(a) 172.185 N
(b) 
Solution:
As per the question:
Mass of the child, m = 22.0 kg
Angle, 
Now,
(a) The magnitude of the normal force exerted by the slide on the child:


Now,
(b) The angle from the horizontal at which the force is directed is:

Answer:
Nora's boat is moving towards Sam at 5 km/hr
Explanation:
The question says that Nora is few meters behind Nancy and is still with respect to her that means the relative velocity between Nora and Nancy is zero
Vrel = 5 - Vnora= 0 ⇒ Vnora = 5km/hr
Pictorially we can represent the given condition as:
Nora-------few meters------Nancy ----------------- Sam
5km/hr 5km/hr →
Hence, Nora's boat is moving towards Sam at 5km/hr.
I can not solve the problem if I do not have the mass.
The expression of the electric flux is

Here,
Q = Total charge enclosed in the closed surface
= Permittivity due to free space
Rearranging to find the charge,

Replacing with our values we have finally



The charge enclosed by the box is 0.1684nC
The sign of the charge can be decided by using the direction of the flux. The charge enclosed by the cube can be calculated by using the electric flux and the permitivity of free space.