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rusak2 [61]
3 years ago
8

What is the value of work done on an object when a 70-newton force moves it 9.0 meters in the same direction as the force?

Physics
2 answers:
kompoz [17]3 years ago
8 0
W=F(ΔX)cosθ
W=70N(9.0m)cos0°
W=630J
DedPeter [7]3 years ago
5 0
We know that:
W=Fs
W=70N*9m
W=630J
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AURORKA [14]

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As we are changing the amplitude in the simulation there is no change in the speed frequency and wavelength.

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3 years ago
Please help I'm stuck on this question ​
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Explanation:

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8 0
2 years ago
Draw vectors to represent these motions:<br>moving 3 cm to the right<br>moving 2 cm to the left
Ira Lisetskai [31]
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7 0
2 years ago
A knight moves on a chessboard two squares up, down, left, or right followedby one square in one of the two directions perpendic
Contact [7]

Answer:

Explanation:

Check attachment for solution.

Generally the movement of the knight is L, i.e (2,1), (1,2),(-1,2),(1,-2) etc.

So using Pythagoras theorem

x^2+y^2=1^2+2^2

x^2+y^2=5

Then, the knight will make one movement when the displacement is √5.

So let take a look at other positions

(1,0),(0,1),(-1,0), (0,-1).

Then, for us to have this kind of movement, the knight has to make 3 movements.

When the displacement is 1, then it will make 3 movement.

Let examine other positions

(2,2) or(-2,-2) or (2,-2) or (-2,2)

When the displacement is √8

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5 0
3 years ago
Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti
Andreas93 [3]
Answer: 1.88 N

Explanation:

Data:

Force = 4.00N
angle = 62°
horizontal force = ?

Solution:

The trigonometric ratio that relates horizontal - leg to hypotenuse is the cosine.

That ratio is:

                        horizontal - leg
cos(angle) = -------------------------
                          hypotenuse

So, applied to the force, that is:

                             horizontal force
cos (angle) = -----------------------------------
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So, clearing the horizontal component you get:
                                         
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Substitute the data given:

horizontal force = 4.00N * cos(62°) = 4.00N * 0.4695 = 1.88 N

Answer: 1.88N


7 0
3 years ago
Read 2 more answers
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