What is the value of work done on an object when a 70-newton force moves it 9.0 meters in the same direction as the force?

Physics

2 answers:

kompoz [17]3 years ago

8 0

W=F(ΔX)cosθ
W=70N(9.0m)cos0°
W=630J

DedPeter [7]3 years ago

5 0

We know that:
W=Fs
W=70N*9m
W=630J

You might be interested in

Write down the boiling point and freezing point of mercury an alcohol

nekit [7.7K]

Mercury has a high boiling point of 357 degrees C.
Mercury has a freezing point of −39 degrees C.

8 0

3 years ago

When energy is converted from one form to another in a chemical or physical change, which of the following also changes by a mea

ArbitrLikvidat [17]

Answer:

None of the above

Explanation:

When energy is converted from one form to another in a chemical or physical change, none will change. This is due to the law of conservation of energy. It states that the total energy of the system remains constant. It only changes energy from one form of energy to another. So, the correct option is (d) "none of the above".

3 0

3 years ago

(A) how much work is done when you push a crate horizontally with 100 N across a 10-m factory floor?

Mila [183]

Answer:

A) 1000 joules

Explanation:

In general work is given by the equation:

$W=\intop_{a}^{b}\overrightarrow{F}\cdot d\overrightarrow{s}$ (1)

A) With $\overrightarrow{s}$ the displacement and $\overrightarrow{F}$ the force applied, because the force and the displacement are parallel (the crate is pushed horizontally) $\overrightarrow{F}\cdot d\overrightarrow{s}$ is simply $F\,ds$ , and because the path is a straight line and the force is constant work is:

$W=FS$ (2),

$W=(100)(10)=1000\,J$

B) The work-energy theorem says that the total work on a body is equal to the change on kinetic energy:

$W_{tot}=\varDelta K$ (3)

The total work on the crate is the work done by the push and plus the work of the friction $W_{tot}=W + W_{f}$ (4) , as (A) because forces are parallel to the displacement $W= FS$ (5) and $W_{f}=-fS$ (6), the due friction always has negative sign because is opposite to the displacement, using (6), (5) and (4) on (3):