Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Answer:
Step-by-step explanation:
Explicit formula of the sequence,
Answer:
I dont think so I would look at it as how did they get the -2
Answer:
729
Step-by-step explanation:
hope this helps!
Answer:
You would have 1/6 of your money remaining.
Step-by-step explanation:
Let's write an equation for this.
1 - (2/3 + 1/6)
First, let's multiply the numerator and denominator of 2/3. You get 4/6!
1 - (2/3 + 1/6)
1 - (4/6 + 1/6)
Next, let's add 4/6 and 1/6. You get 5/6!
1 - (4/6 + 1/6)
1 - 5/6
Finally, let's turn 1 into 6/6 and do 6/6 - 5/6!
1 - 5/6
6/6 - 5/6
1/6
You would have 1/6 of your money remaining.
