Big Al stands on a skateboard at a rest and throws a 0.5-kilogram rock at a velocity of 10.0 m /sec. Big Al moves back at 0.05 m
1 answer:
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Answer:
Explanation:
Data provided in the question:
Height above the ground, H= 5.0m
Range of the ball, R= 20 m
Initial horizontal velocity =
Initial vertical velocity= (Since ball was thrown horizontally only)
Acceleration acting horizontally, = 0 m/s² [ Since no acceleration acts horizontally) ]
Vertical Acceleration, = 9.8 m/s² (Since only gravity acts on it)
Let 't' be the time taken to reach ground
Therefore, using equations of motion, we have
Then using Equations of motion for horizontal motion,
Answer:
is the current through the body of the man.
energy dissipated.
Explanation:
Given:
- time for which the current lasted,
- potential difference between the feet,
- resistance between the feet,
<u>Now, from the Ohm's law we have:</u>
is the current through the body of the man.
<u>Energy dissipated in the body:</u>