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scoundrel [369]
3 years ago
11

What type of diagram is this?

Physics
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer: That’s a sankey diagram

Explanation:

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newtons 3rd law of motion states that "every action has an equal and oppisite reaction" A golf ball was hit with a force of 200
jolli1 [7]
This relates to newtons law of motion because that golf ball hit so hard that it went the same speed. because its force the more u like hit it your gonna get that force.
hope this makes sense

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What will happen to the period of a ball-on-a-spring if the ball is replaced by a smaller one with half the mass
Murrr4er [49]

When the ball on a spring is replaced by a smaller ball with half the mass :  The period decrease by 29%

<h3>Calculate the Period </h3>

We will apply the formula below to calculate period

T = 2\pi \sqrt{\frac{m}{k } }

 where :

T₁ / T₂ = \sqrt{\frac{m_{1} }{m_{2} } }    where m₂ = m₁ / 2

Therefore :

T₂ = \frac{T_{1} }{\sqrt{2} }   = 0.71 T

Hence we can conclude that the period will decrease by 29% ( i.e 100 - 71 ).

Learn more about Period calculation : brainly.com/question/10728818

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2 years ago
What is the smallest part of an element?<br> An atom
KatRina [158]

Answer:

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Explanation:

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A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.
enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, KE_{0}  = 0.5 mu^{2}

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, KE_{f} = 0.5mv^{2}

a) Using the principle of energy conservation,

KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

7 0
4 years ago
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