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3 years ago

What is the difference between kinetic and mechanical energy?

Physics

2 answers:

Wittaler [7]3 years ago

8 0

Kinetic energy is energy that is in motion, thats all I remember

vitfil [10]3 years ago

8 0

Mechanical energy is a form of energy, it represents the energy that is possessed by a mechanical system of device due to its motion or position. Stated differently, mechanical energy is the ability of an object to do work. Mechanical energy can be either kinetic (energy in motion) or potential (energy that is stored)

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Why it is difficult to run fast in sand

balu736 [363]

Running on sand requires 1.6 times more energy spent than running on hard surface, so the force applied by our foot on sand is less.

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2 years ago

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Which statement best describes the adiabatic process?

kupik [55]

Answer:

diaetes

Explanation:

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2 years ago

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Two planets A and B, where B has twice the mass of A, orbit the Sun in elliptical orbits. The semi-major axis of the elliptical

lozanna [386]

Answer:

2.83

Explanation:

Kepler's discovered that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit, that is called Kepler's third law of planet motion and can be expressed as:

$T=\frac{2\pi a^{\frac{3}{2}}}{\sqrt{GM}}$ (1)

with T the orbital period, M the mass of the sun, G the Cavendish constant and a the semi major axis of the elliptical orbit of the planet. By (1) we can see that orbital period is independent of the mass of the planet and depends of the semi major axis, rearranging (1):

$\frac{T}{a^{\frac{3}{2}}}=\frac{2\pi}{\sqrt{GM}}$

$\frac{T^{2}}{a^{3}}=(\frac{2\pi }{\sqrt{GM}})^2$ (2)

Because in the right side of the equation (2) we have only constant quantities, that implies the ratio $\frac{T^{2}}{a^{3}}$ is constant for all the planets orbiting the same sun, so we can said that:

$\frac{T_{A}^{2}}{a_{A}^{3}}=\frac{T_{B}^{2}}{a_{B}^{3}}$

$\frac{T_{B}^{2}}{T_{A}^{2}}=\frac{a_{B}^{3}}{a_{A}^{3}}$

$\frac{T_{B}}{T_{A}}=\sqrt{\frac{a_{B}^{3}}{a_{A}^{3}}}=\sqrt{\frac{(2a_{A})^{3}}{a_{A}^{3}}}$

$\frac{T_{B}}{T_{A}}=\sqrt{\frac{2^3}{1}}=2.83$

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3 years ago

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An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's fi

lana66690 [7]

The height difference is found by
$\delta H=400sin(5 \°)=34.86m$
Then the change in potential energy is
$E=mgh=(80.0kg)(9.8 \frac{kgm}{s^2})(34.86)= 27332J$

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3 years ago

How can i find the acceleration?(rope and grinder have no weight) *** sorry for my english

Finger [1]

The main formula to be used here is

Force = (mass) x (acceleration).

We'll get to work in just a second. But first, I must confess to you that I see
two things happening here, and I only know how to handle one of them. So
my answer will be incomplete, but I believe it will be more reliable than the
first answer that was previously offered here.

On the right side ... where the 2 kg and the 3 kg are hanging over the same
pulley, those weights are not balanced, so the 3 kg will pull the 2kg down, with
some acceleration. I don't know what to do with that, because . . .

At the same time, both of those will be pulled up by the 10 kg on the other side
of the upper pulley.

I think I can handle the 10 kg, and work out the acceleration that IT has.

Let's look at only the forces on the 10 kg:

-- The force of gravity is pulling it down, with the whatever the weight of 10 kg is.

-- At the same time, the rope is pulling it UP, with whatever the weight of 5 kg is ...
that's the weight of the two smaller blocks on the other end of the rope.

So, the net force on the 10 kg is the weight of (10 - 5) = 5 kg, downward.

The weight of 5 kg is (mass) x (gravity) = (5 x 9.8) = 49 newtons.

The acceleration of 10 kg, with 49 newtons of force on it, is

Acceleration = (force) / (mass) = 49/10 = 4.9 meters per second²

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2 years ago