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2 years ago

What is the combined gas law?

1 answer:

8 0

Answer: The combined gas law is a combination of Boyle's Law and Charles' Law. The relationship between pressure, volume, and absolute temperature are all present in the combined gas law. It is written mathematically as:

PV/T=k (constant)

The constant, k, will also depend on the number of moles and could therefore vary. As long as the number of moles is constant, k, will be a true constant value.

Most combined gas law are worked with a before condition and an after condition. We typically number these conditions of state as 1 and 2 (sometimes initial and final also). So the working form of the combined gas law is:

P1V1/T1=P2V2/T2

Any units will work here for pressure and volume but the temperature must be absolute (Kelvin).

Explanation:

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What is the mass (in g) of 0. 935 mol of acetone CH3COCH3 the molar mass of acetone is 58. 08 g∙mol^–1.

Ray Of Light [21]

Answer:

54.30 grams acetone

Explanation:

(0. 935 mol)*(58.08 g/mole) = 54.30 grams acetone

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1 year ago

Read 2 more answers

Calculate the energy required to melt 21 g of ice at 0 oC.

vladimir1956 [14]

We are given:

Mass of ice = 21 grams

The ice is already at 0°c, the temperature at which it melts to form water

Molar heat of fusion of Ice = 6.02 kJ/mol

Finding the energy required:

Number of moles of Ice:

Molar mass of water = 18 g/mol

Number of moles = given mass/ molar mass

Number of moles = 21 / 18 = 7/6 moles

Energy required to melt the given amount of ice:

Energy = number of moles * molar heat of fusion

Energy = (7/6) * (6.02)

Energy = 7.02 kJ OR 7020 joules

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3 years ago

When calcium carbonate reacts with hydrochloric acid, calcium ions are transferred to the solution. Write only one net ionic equ

nika2105 [10]

Answer:

In conclusion, the net ionic equation for the reaction between calcium carbonate and hydrochloric acid is CaCO3 solid plus two H+ aqueous react to form Ca2+ aqueous plus CO2 gas plus H2O liquid.

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2 years ago

A solution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the b

Finger [1]

Answer : The molar mass of the solute will be 87.90 g/mol.

Explanation : We know the formula for elevation in boiling point, which is

Δt = i $K_{b}$ m

given that, Δt = 0.357, $K_{b}$ = 5.02 and mass of $CCl _{4}$ = 40,

on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X $10^{-3}$ .
Now, 0.250/ 2.844 X $10^{-3}$ = 87.90 g/mol. which is the weight of unknown component.

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3 years ago

WILL MARK BRAINLIEST!!

frozen [14]

Answer:

Na 1s2 2s2 2p6 3s1

Ar 1s2 2s2 2p6 3s2 3p6

Explanation:

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3 years ago