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natka813 [3]
3 years ago
12

The critical mass of fissionable material is the largest mass necessary to sustain a nuclear fission chain reaction. single mass

value that can sustain a nuclear fission chain reaction. mass at the critical point, which can sustain a nuclear fission chain reaction. smallest mass necessary to sustain a nuclear fission chain reaction.
Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

smallest mass necessary to

Explanation:

The critical mass for a fissionable material is the smallest and the lowest quantity of a particular fissile material required to generate a self-sustaining fission chain reaction under specified conditions. The size's features are determined by a number of variables. Examples include;

The type of fissile material employed, its purity as well as concentration, the shape of the surrounding reaction system e.t.c.

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Is green ink homogeneous or heterogeneous?
Leno4ka [110]
<span>Green ink is homogeneous.
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7 0
3 years ago
A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?
Sonbull [250]

Answer: Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.

Explanation:

The number of moles in the solution will remain same on dilution and thus according to Molarity Equation:

M_1V_1=M_2V_2

M_1= molarity of first solution

V_1= Volume of first solution

M_2= molarity of second solution

V_2= Volume of second solution

0.1\times 2.00L=1.75M\times V_2

V_2=0.114L=114ml

Thus 114 ml of 1.75 M solution is taken and the volume is diluted to 2.0 L to make 0.100 M solution.










3 0
3 years ago
Read 2 more answers
50.0 mL of a solution of HCl is combined with 100.0 mL of 1.05M NaOH in a calorimeter. The reaction mixture is initially at 22.4
VikaD [51]

Answer:

2.1 M is the molarity of the HCl solution.

Explanation:

HCl+NaOH\rightarrow H_2O+NaCl

Molarity of HCl solution = M_1=?

Volume of HCl solution = V_1=50.0mL

Ionizable hydrogen ions in HCl = n_1=1

Molarity of NaOH solution = M_2=1.05 M

Volume of NaOH solution = V_2=100.0 mL

Ionizable hydroxide ions in NaOH = n_2=1

n_1M_1V_1=n_2M_2V_2 (neutralization )

M_1=\frac{M_2V_2}{V_1}=\frac{1.05M\times 100.0 mL}{50.0 mL}

M_1=2.1 M

2.1 M is the molarity of the HCl solution.

3 0
3 years ago
How many liters of 1.2M solution can be prepared with 0.50 moles of C6H12O6
BigorU [14]
First you need to know the molecular weight of sugar (C6H12O6) which is 180.156g/mol
You have half a mole so you have 90.078g
If you wanted to make 1L of a 1.2M solution of glucose you would need 180.156*1.2=216.1872g
But you only have 90.078g
So you need to figure out how much this 90.078g will make if the solution must be 1.2M:
90.078g/216.1872g=xL/1L
solve for the X and you get 0.416666666...
so 416.7ml or 0.417L
5 0
3 years ago
Please help me!!!!!!!!
Semmy [17]
Surface runoff, its quite obvious in the picture

3 0
3 years ago
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