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WINSTONCH [101]
2 years ago
12

What quantity of aluminium is deposited when a current of 10A is passed through a solution of aluminium salt for 1930s? (All=27,

F=96500cmol)​
Chemistry
1 answer:
Arlecino [84]2 years ago
6 0

Answer:

AL*3+ + 3e- =AL.

(10A×1930)÷96500=0.2mole e-

0.2÷3×27=1.8g(AL)

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Answer:

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4 0
2 years ago
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Answer:

339kJ

Explanation:

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