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3 years ago

The new Bamo Super Ball has a rebound ratio of 0.97. If you dropped the ball from a

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

92.18 feet

Step-by-step explanation:

t(n)=125(.97)^x

t(10)=124(.97)^10

Sequence cant have partial or discrete bounce

ololo11 [35]3 years ago

5 0

Answer:

92.18 ft

Step-by-step explanation:

The rebound ratio 0.97 means the ball will rebound 97% of its height on the previous bounce.

Bounce Height

1 125(0.97) = 121.25

2 125(0.97)(0.97) = 117.6125

3 125(0.97)(0.97)(0.97) = 114.084125

See a pattern?

Bounce Height

1 125(0.97)

2 125(0.97)^2

3 125(0.97)^3 the exponent matches the bounce number

Tenth bounce:

10 125(0.97)^10 = 92.18 (rounded to 2 places)

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The points (0, 1) and (-9, -9) fall on a particular line. What is its equation in slope-intercept form?

prohojiy [21]

The slope-intercept form:

$y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

m - slope

b - y-intercept → (0, b)

We have the points (-9, -9) and (0, 1) - y-intercept → b = 1.

Calculate the slope:

$m=\dfrac{1-(-9)}{0-(-9)}=\dfrac{10}{9}$

Answer: $y=\dfrac{10}{9}x+1$

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3 years ago

Mrs. Chu's famous peanut butter cookies call for 1 cup of peanut butter for every 1/2 of a cup of oil. Today, she wants to make

lesantik [10]

Answer:

she should use 2 cups of peanut butter

Step-by-step explanation:

to know the answer to that

use this equation (pb is peanut butter &o is oil)

1cup of pb=1/2 cup of o

?=1 cup of o

1×1÷1/2= 1×1×2/1=2co cups of pb

5 0

3 years ago

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

3 years ago

What’s 18x3+12-1x34+13-2x56?

Alina [70]

18 x 3 + 12 - 1 x 34 + 13 - 2 x 56 = 67

<=Work=>

18 x 3 = 54

1 x 34 = 34

2 x 56 = 112

(54) + 12 - (34) + 13 - (112)

66 - 34 + 13 - 112

32 + 13 - 112

45 - 112

= 67

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3 years ago

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TEA [102]

Step-by-step explanation:

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3 0

3 years ago

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