Answer:
The solvent is Nitrogen and the solute is oxygen
Explanation:
Normally the solvent always contains higher amount of substance than the solute in a particular solution
The solubility of Lead(II)Fluoride is 2.17 × 10⁻³ g/L in water at 25°C.
At a specific solution temperature, a solid salt compound can entirely dissolve in pure water up to a predetermined molar solubility limit. The dissociation stoichiometry ensures that the molarities of the constituent ions are proportionate to one another. The saturable nature of the solution causes them to also coexist in a solubility equilibrium with the solid component. At this temperature, a solubility product constant Ksp is calculated using the solubility product of their molarity values.
Lead (II) fluoride has the following solubility equilibrium for its saturated solution:
⇄ 
![K_s_p = [Pb^2^+][F^-]^2](https://tex.z-dn.net/?f=K_s_p%20%3D%20%5BPb%5E2%5E%2B%5D%5BF%5E-%5D%5E2)
This compound dissociates in a 1:2 ratio of ions. For the compound dissolved in pure water, the Ksp is expressed in terms of the molar solubility "x" as:


Here,
× 
4.1 × 10⁻⁸ = 4 x³
x³ = 1.025 × 10⁻⁸
x³ = 10.25 × 10⁻⁹
x = 2.17 × 10⁻³ g/L
Therefore, the solubility of Lead(II)Fluoride is 2.17 × 10⁻³ g/L.
Learn more about solubility here:
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Fossil evidence, rocks, and the shape of continents provide support for the theory of plate tectonics.
hope this helps, God bless!
Multiply the weight of the object by the distance it traveled to find the amount of work output. For the example: 10 lbs. x 1 foot = 10 foot-pounds. Find the work efficiency by dividing the work output by the work input and multiplying by 100.
Answer:

Explanation:
<u>1. Rewrite the equation in a more appropriate format for a better understanding: </u>

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<u>2. Multiply the whole equation (both sides) by 84.01 × 52.5 to eliminate the denominators:</u>

<u>3. Do the operations:</u>

<u>4. Add like terms:</u>

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<u>5. Divide both sides by 115.93:</u>
