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Contaminants such as fertilizers, pesticides, and animal waste being released into nearby air and water can cause ___

mylen [45]

Answer:

The answer is D all of the above

Explanation:

7 0

3 years ago

How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?

DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

$H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O$

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

$2*n_{acid}=n_{base}$

And in terms of concentrations and volumes:

$2*M_{acid}V_{acid}=M_{base}V_{base}$

Thus, we solve for the volume of acid:

$V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL$

Best regards.

5 0

3 years ago

Name the following compound:

lawyer [7]

Answer:

thjvfghjjvvjj

Explanation:

Assume that the set of conditionals is true. Use the Law of Syllogism to

write a true conditional.

8. If two numbers are odd, the

answer is that a

even, then the number is divisible by 2.

Enter your answer.

CHECK ANSWER

6 0

1 year ago

Hydrogen gas and nitrogen gas come together to form ammonia. If 25.0 g of nitrogen is mixed with hydrogen, what volume of hydrog

jeka94

Answer:

60.0L of hydrogen are needed

Explanation:

Based on the reaction:

3H₂ + N₂ ⇄ 2NH₃

3 moles of hydrogen react 1 mole of nitrogen.

To solve this question we have to find the moles of nitrogen. With the moles of nitrogen we can find the moles of hydrogen. Using PV = nRT at STP conditions we can find the volume as follows:

Moles Nitrogen -Molar mass: 28g/mol-

25.0g N₂ * (1mol / 28g) = 0.893 moles N₂

Moles hydrogen:

0.893 moles N₂ * (3mol H₂ / 1mol N₂) = 2.679 moles H₂

Volume hydrogen:

PV = nRT

V = nRT / P

Where V is volume in liters,

n are moles of the gas: 2.679 moles

R is gas constant: 0.082atmL/molK

T is absolute temperature: 273.15K at STP

P is 1atm at STP

Replacing:

V = 2.679mol*0.082atmL/molK*273.15K / 1atm

V =

<h3>60.0L of hydrogen are needed</h3>

6 0

3 years ago

Which process would require the least amount of energy? Which process would require the least amount of energy? the process for

oee [108]

Answer:

The process of the first ionization energy

Explanation:

The ionization energy is the energy required to remove one electron for one isolated atom at the gas phase. The first electron to be removed is the valence electron which is far away from the nuclei. Because of that, this electron suffers a less attraction force.

For the second ionization energy, the electron will be closer to the nuclei, so it is more attracted, then a large amount of energy is necessary to remove it. For the third, the amount of energy will be larger. So, the first ionization energy requires the least amount of energy.

3 0

4 years ago