Who often does galeras erupt
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Answer : 87.60 g of Urea.
Explanation : We need to use the mole fraction formula here;
So, we have values and substituting them we get, 29.45 =
(31.8)
Hence, = 0.926 (this is the mole fraction of water)
Therefore, mole fraction of urea = 1 - 0.926 = 0.074,
moles of water present = 329 g / 18.0 mol = 18.27 moles,
Now, we have 0.074 moles of urea / 0.926 moles of water = x moles of urea / 18.27 moles of water,
Therefore, x = 1.46 moles of urea.
And now, Mass of urea = moles of urea X molar mass of urea;
= 1.46 X 60.0 = 87.60 g
Hence the mass of urea to be dissolved in 329 g of water will be 87.60 g
Explanation : We need to use the mole fraction formula here;
So, we have values and substituting them we get, 29.45 =
Hence,
Therefore, mole fraction of urea = 1 - 0.926 = 0.074,
moles of water present = 329 g / 18.0 mol = 18.27 moles,
Now, we have 0.074 moles of urea / 0.926 moles of water = x moles of urea / 18.27 moles of water,
Therefore, x = 1.46 moles of urea.
And now, Mass of urea = moles of urea X molar mass of urea;
= 1.46 X 60.0 = 87.60 g
Hence the mass of urea to be dissolved in 329 g of water will be 87.60 g
From the diagram, structure 1 would be the chloroplast and it represents the site of photosynthesis.
<h3>Plant cells</h3>The image (see attached) is that of a plant cell and structure labeled 1 is the chloroplast.
The chloroplast of plant cells acts as the site of photosynthesis where inorganic materials are used to synthesize carbohydrates.
Plants generally serve as producers in food chains and thus, chloroplast helps sustain life.
More on plant cells can be found here: brainly.com/question/1894299
