Find the moles of CaO
divide mass (2.0g) by the RFM which is 56 (Ca is 40 add that to O which is 16 making 56) this gives 0.0356 moles.
Find the theoretical mass by multiplying the moles of CaO (which is 0.0356 as there are no balancing number making the ratio 1:1) by the RFM of Ca(OH)2 which is 74 (40+16+16+1+1)
74 (Ca(OH)2 RFM) x 0.0357 (CaO moles) = 2.6g which is the theoretical mass of Ca(OH)2
Find percentage yield by dividing the actual mass of Ca(OH)2 by the theoretical and then x100 this Should give you 82.3%
The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃
- For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.
- According to the question, we are to write a balanced equation for the reaction in aqueous solution for cesium carbonate and magnesium nitrate
- The chemical formula for Cesium carbonate is Cs₂CO₃
- The chemical formula for magnesium nitrate is Mg(NO₃)₂
Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃
Learn more here: brainly.com/question/11904811
Statement that when two elements combine with each other to from more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.
1.33 is the answer thank me later
