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vodomira [7]
3 years ago
9

Calculate # of atoms in 46g of Na

Chemistry
1 answer:
makvit [3.9K]3 years ago
5 0

21Explanation:BEACUSE I CAN

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Write the step by step process of digestion in ruminants using 4 square method.
Vaselesa [24]

The digestion process in Ruminants begins by chewing and swallowing their food.

<h3>What are ruminants?</h3>

A ruminant is any herbivorous animal that has a stomach with four compartments, which are tasked with acquiring nutrients from plant-based food by fermenting it prior to digestion.

The digestion process in Ruminants begins by chewing and swallowing their food. Ruminants do not completely chew the food they eat, but just consume or gulp as much they can and then swallow the food. This is actually an adaptation by which these animals have evolved to spend as little time as possible feeding so that they are not hunted down by any predators while they are eating.

As mentioned earlier, the stomach of these Ruminants is divided into 4 chambers – rumen, reticulum, omasum, and the abomasum.

The process of digestion begins with the first two chambers of the stomach, the rumen and reticulum by softening the ingested matter. Later the microbes present in the rumen produces the cellulase enzymes required to digest the cellulose.

Once the plant fibres have been broken down to provide vitamins, proteins, and other organic acids, the nutrients are absorbed into the animal’s bloodstream.

Coarse plants are sent further into the next chamber for further digestion. Here is where the further bacterial action takes place and the food is formed into soft chunks called the cud.

This cud produced is regurgitated back into the animal’s mouth where it can be chewed again. The saliva of the cow greatly aids in digesting the cud.

After chewing, the food bypasses the two chambers of the stomach and directly enters the third chamber. The walls of the third chamber mash and compact the food molecules further, and then pass it to the fourth chamber – the abomasum.

The final digestion in the stomach is carried by the abomasum and then passed to the intestine.

Learn more about the ruminants here:

brainly.com/question/26752412

#SPJ1

3 0
2 years ago
In a mixture of argon and hydrogen occupying a volume of
kobusy [5.1K]

This isn't a full question!

3 0
4 years ago
An aqueous solution of sodium hydroxide is standardized by titration with a 0.170 M solution of perchloric acid. If 28.5 mL of b
Ray Of Light [21]

Answer:

0.095M

Explanation:

HClO4 + NaOH = NaClO4 + H2O

Concentration of acid CA= 0.170M

Concentration of base CB= ???

Volume of base VB= 28.5ml

Volume of acid VA= 16.0ml

Number of moles of acid nA= 1

Number of moles of base nB= 1

From

CAVA/CBVB= nA/nB

CB= CAVAnB/VBnA

CB= 0.170×16.0×1/28.5×1

CB= 0.095M

4 0
3 years ago
What is the mass of 6.14x10^25 atoms of gold
Alexxx [7]

3452.6^15 atoms of gold.

3 0
3 years ago
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0
3 years ago
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