C) accretionary-wedge complex.
Explanation:
The accretionary wedge complex is a thick accumulation of sediments and small tectonic blocks formed from materials scraped off subducting oceanic lithosphere at a convergent margin.
Space between the subducting plate and the less dense plate gets filled by sediments scraped off the subducting plate and this forms a wedge like sediment called the accretionary wedge.
- The accretionary wedge is invariably made up of materials found on the ocean floor.
- Under extreme conditions, some parts of wedge transforms into metamorphic rocks.
- The wedge is made up of: pelagic sediments, ocean floor basalts e.t.c
Learn more:
Sedimentary rocks brainly.com/question/9131992
#learnwithBrainly
Answer: Their final relative velocity is -0.412 m/s.
Explanation:
According to the law of conservation,
![m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v](https://tex.z-dn.net/?f=m_%7B1%7Dv_%7B1%7D%20%2B%20m_%7B2%7Dv_%7B2%7D%20%3D%20%28m_%7B1%7D%20%2B%20m_%7B2%7D%29v)
Putting the given values into the above formula as follows.
![m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v](https://tex.z-dn.net/?f=m_%7B1%7Dv_%7B1%7D%20%2B%20m_%7B2%7Dv_%7B2%7D%20%3D%20%28m_%7B1%7D%20%2B%20m_%7B2%7D%29v)
![2.50 \times 10^{3} kg \times 0 m/s + 7.50 \times 10^{3} kg \times -0.550 m/s = (2.50 \times 10^{3} kg + 7.50 \times 10^{3} kg)v](https://tex.z-dn.net/?f=2.50%20%5Ctimes%2010%5E%7B3%7D%20kg%20%5Ctimes%200%20m%2Fs%20%2B%207.50%20%5Ctimes%2010%5E%7B3%7D%20kg%20%5Ctimes%20-0.550%20m%2Fs%20%3D%20%282.50%20%5Ctimes%2010%5E%7B3%7D%20kg%20%2B%207.50%20%5Ctimes%2010%5E%7B3%7D%20kg%29v)
![-4.12 \times 10^{3} kg m/s = (10^{4} kg) v](https://tex.z-dn.net/?f=-4.12%20%5Ctimes%2010%5E%7B3%7D%20kg%20m%2Fs%20%3D%20%2810%5E%7B4%7D%20kg%29%20v)
v = ![\frac{-4.12 \times 10^{3} kg m/s}{10^{4} kg}](https://tex.z-dn.net/?f=%5Cfrac%7B-4.12%20%5Ctimes%2010%5E%7B3%7D%20kg%20m%2Fs%7D%7B10%5E%7B4%7D%20kg%7D)
= -0.412 m/s
Thus, we can conclude that their final relative velocity is -0.412 m/s.
Answer:
A. the total net force is 14
B. the total net force is 15
Explanation:
Answer:
Explanation:
Let fuel is released at the rate of dm / dt where m is mass of the fuel
thrust created on rocket
= d ( mv ) / dt
= v dm / dt
this is equal to force created on the rocket
= 220 dv / dt
so applying newton's law
v dm / dt = 220 dv / dt
v dm = 220 dv
dv / v = dm / 220
integrating on both sides
∫ dv / v = ∫ dm / 220
lnv = ( m₂ - m₁ ) / 220
ln4000 - ln 2500 = ( m₂ - m₁ ) / 220
( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )
( m₂ - m₁ ) = 220 x ( 8.29 - 7.82 )
= 103.4 kg .
Answer:
a).β=0.53
T
a).β=0.40
T
Explanation:
The magnetic field at distance 'r' from the center of toroid is given by:
![\beta =\frac{u_{o}*I*N}{2\pi*r}](https://tex.z-dn.net/?f=%5Cbeta%20%3D%5Cfrac%7Bu_%7Bo%7D%2AI%2AN%7D%7B2%5Cpi%2Ar%7D)
a).
![N=500\\I=0.800A\\r=15cm*\frac{1m}{100cm}=0.15m\\u_{o}=4\pi x10^{-7}\frac{T*m}{A} \\\beta=\frac{4\pi x10^{-7}\frac{T*m}{A}*0.8A*500}{2\pi*0.15m} \\\beta=0.53x10^{-3}T](https://tex.z-dn.net/?f=N%3D500%5C%5CI%3D0.800A%5C%5Cr%3D15cm%2A%5Cfrac%7B1m%7D%7B100cm%7D%3D0.15m%5C%5Cu_%7Bo%7D%3D4%5Cpi%20x10%5E%7B-7%7D%5Cfrac%7BT%2Am%7D%7BA%7D%20%20%5C%5C%5Cbeta%3D%5Cfrac%7B4%5Cpi%20x10%5E%7B-7%7D%5Cfrac%7BT%2Am%7D%7BA%7D%2A0.8A%2A500%7D%7B2%5Cpi%2A0.15m%7D%20%5C%5C%5Cbeta%3D0.53x10%5E%7B-3%7DT)
b).
The distance is the radius add the cross section so:
![r_{1}=15cm+5cm\\r_{1}=20cm](https://tex.z-dn.net/?f=r_%7B1%7D%3D15cm%2B5cm%5C%5Cr_%7B1%7D%3D20cm)
![r_{1} =20cm*\frac{1m}{100cm}=0.20m](https://tex.z-dn.net/?f=r_%7B1%7D%20%3D20cm%2A%5Cfrac%7B1m%7D%7B100cm%7D%3D0.20m)
![\beta =\frac{u_{o}*I*N}{2\pi*r1}](https://tex.z-dn.net/?f=%5Cbeta%20%3D%5Cfrac%7Bu_%7Bo%7D%2AI%2AN%7D%7B2%5Cpi%2Ar1%7D)
![\beta =\frac{4\pi x10^{-7}*0.80A*500 }{2\pi*0.20m} \\\beta=0.4x10^{-3} T](https://tex.z-dn.net/?f=%5Cbeta%20%3D%5Cfrac%7B4%5Cpi%20x10%5E%7B-7%7D%2A0.80A%2A500%20%7D%7B2%5Cpi%2A0.20m%7D%20%5C%5C%5Cbeta%3D0.4x10%5E%7B-3%7D%20T)