All categories

3 years ago

Using the Particle Theory, explain why liquids are less compressible than gases.

Physics

1 answer:

AleksandrR [38]3 years ago

5 0

Explanation:

In liquids the particles have more energy. This allows the particles in liquids to roll past each other, but they are still tightly packed. Gases can be compressed because the particles can be forced closer together. The particles in a liquid are already as close as they can be.

You might be interested in

How are fingerprints identified and collected at the crime scene?

padilas [110]

One of the most common methods for discovering and collecting latent fingerprints is by dusting a smooth or nonporous surface with fingerprint powder (black granular, aluminum flake, black magnetic, etc.). If any prints appear, they are photographed as mentioned above and then lifted from the surface with clear adhesive tape. The lifting tape is then placed on a latent lift card to preserve the print.

4 0

3 years ago

An electron having 500ev energy enters at right angle to a uniform magnetic field of 10^-4 Tesla. If its specific charge is 1.75

gtnhenbr [62]

Answer:

The correct answer might be $r = 2.8^{27}$ meters.

Explanation:

<u>The Answer Given might not be correct, I just did what my brain said.</u>

As the angle is perpendicular so Θ=90.

Putting this in the equation to calculate the magnetic force as:

F = evBsinΘ

F= evBsin90 *sin90 = 1 so,

F= evB.

Now when the electron will start to move in a circle, The necessary force that makes the electron rotate in a circle is given by Centripetal force.

So,

Magneteic Force = Centripetal Force

evB = $\frac{mv^{2} }{r}$

r = $\frac{mv}{Be}$ ......(1)

Now the problem is, We don't know " v " so we need to calculate velocity first,

Calculation of Velocity:

In order to calculate the velocity of electron, We should know the potiential difference with which the electrons are accelerated which in our case is 500ev. If "V" is the potiential difference, the energy gained by electrons during accelreation will be Ve. This appear as kinectic enrgy of electrons as,

K.E = Ve

$\frac{1}{2}$ m $v^{2}$ = Ve

v = $\sqrt{\frac{2ve}{m} }$ ................(2)

Putting value of velocity in equation 2 from 1:

r = $\frac{mv}{Be}$ $\sqrt{\frac{2ve}{m} }$

$r = \sqrt{\frac{2mev}{Be}}$

$r = \sqrt{\frac{(2)(9.1^{-31})(500) (1.6^{-19} ) }{ (1.75^{11} ) (10^{-4} ) } }$

$r = 2.8^{27}$ meters.

8 0

3 years ago

In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2

evablogger [386]

Answer: hello your question is incomplete attached below is the complete question

answer : 1/2 KD^2 ( option A )

Explanation:

P.E ( potential energy ) = mgd

In case 1 P.E = 0 i.e. mgd = 0

Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring

<u>The potential energy of the M in case 2 </u>

= P.E of M at rest + P.E of the spring

= 0 + 1/2 KD^2

4 0

3 years ago

Using dimensional analysis, show that energy can be calculated from the following energy equations. Hint, in SI, here we want Jo

anyanavicka [17]

Explanation:

1. The kinetic energy of any object is calculated as :

$E=\dfrac{1}{2}mv^2$ ...........(1)

Dimensional formula of energy, $[E]=[ML^2T^{-2}]$

Dimensional formula of mass is $[M]$

Dimensional formula of velocity, $[v]=[LT^{-1}]$

$[ML^2T^{-2}]=\dfrac{1}{2}[M]([LT^{-1}])^2$

So, $[ML^2T^{-2}]=[ML^2T^{-2}]$

LHS = RHS

2. The potential energy is given by :

$E=mgh$

Dimensional formula of mass is $[M]$

Dimensional formula of g is $[LT^{-2}]$

Dimensional formula of height is $[L]$

Dimensional formula of energy, $[E]=[ML^2T^{-2}]$

So, $E=[M][LT^{-2}][L]$

So, LHS = RHS

Hence, this is the required solution.

7 0

3 years ago

Two technicians are discussing the FMVSS 135 standards for parking brakes. Technician A states that the hand force required to s

masya89 [10]

Answer:

Technician A

Explanation:

Technician A is correct because, the hand force required is not supposed and even should not exceed 80 lb.

On the other hand, the foot force limit is even higher at 100 lb. Thus, the required foot force break should not exceed 100 lb. We are given 80 lb in the question, which is quite less than 100 lb. It could exceed 80, but must not exceed 100. Thus only Technician A is correct among them both.

5 0

4 years ago