Answer:
23 child tickets were sold
Step-by-step explanation:
Using the information given, we can set up an equation to solve for the number of child tickets sold. Since there were three times as many adult tickets as child tickets sold, we can assign the variable 'x' to represent the number of child tickets and '3x' to represent the number of adult tickets. Since we know the cost of each ticket, as well as the total sales, we can set up the following equation:
5.20x + 9.70(3x) = 788.90
Simplify 5.20x + 29.1x = 788.90
Combine like terms: 34.3x = 788.90
Divide both sides by 34.3: x = 23 child tickets
The correct answer is 720. Just turned it in and got a 100. Good luck and hoped this help ya.
Substitution is where we first Isolate one of the unknowns, express it in terms of the other unknown, and replace the isolated unknown with the other unknown in another equation. So that each time we only need to deal with one unknown. I think you'll get a better idea here:
First name these 2 equations with 1 and 2.
4x + 5y = 7 (1)
y = 3x + 9 (2)
Since y is already isolated in (2), so we can skip the isolation step and continue to substitute.
Substitute (2) into (1).
4x + 5(3x+9) = 7
Expand.
4x + 15x + 45 = 7
Group.
19x + 45 = 7
Shift +45 to the other side and turn it into -45.
19x = 7 - 45
19x = -38
Shift x19 to the other side, turn it into /19.
X = - 38/19
X = - 2
Now we solved x already, we can just substitute x= - 2 back to equation (2).
y = 3(-2) + 9
y = - 6 + 9
y = 3
So, the answers are
x = - 2
y = 3
By definition, the volume of a sphere is:
Where,
r: sphere radio
Substituting values we have:
Rounding the result to the nearest tenth:
Answer: the sphere's volume is: 
Answer: 
Step-by-step explanation:
We can use the Rational Root Test.
Given a polynomial in the form:
Where:
- The coefficients are integers.
- 
is the leading coeffcient (
)
- 
is the constant term 
Every rational root of the polynomial is in the form:
For the case of the given polynomial:
We can observe that:
- Its constant term is 6, with factors 1, 2 and 3.
- Its leading coefficient is 2, with factors 1 and 2.
Then, by Rational Roots Test we get the possible rational roots of this polynomial:
