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3 years ago

Garen is climbing stairs to the castle. He travels a distance of 350 stairs in 5 minutes of time.

Physics

2 answers:

klio [65]3 years ago

8 0

Speed =distance/time
S=D/T
S=350/5
S=70 stairs per minute

KATRIN_1 [288]3 years ago

6 0

The Answer Is 70:1
Hope This Helps You.

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Hey can someone help plzzzzz

ohaa [14]

Answer:

Potential Energy stored = mgh ; m : mass, g : gravitational acceleration (let 10m/s) , h : height

Hence,

Energy Stored in the ball = mgh = (2*10*4) J

= 80 Joules!

8 0

3 years ago

Read 2 more answers

A 100 g ball collides elastically with a 300 g ball that is at rest. If the 100 g ball was traveling

sammy [17]

Answer:

The magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).

Explanation:

We can find the velocity of the two balls after the collision by conservation of linear momentum and energy:

$P_{1} = P_{2}$

$m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}$

Where:

m₁: is the mass of the ball 1 = 100 g = 0.1 kg

m₂: is the mass of the ball 2 = 300 g = 0.3 kg

$v_{1_{i}}$ : is the initial velocity of the ball 1 = 6.20 m/s

$v_{2_{i}}$ : is the initial velocity of the ball 2 = 0 (it is at rest)

$v_{1_{f}}$ : is the final velocity of the ball 1 =?

$v_{2_{f}}$ : is the initial velocity of the ball 2 =?

$m_{1}v_{1_{i}} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}}$

$v_{1_{f}} = v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}}$ (1)

Now, by conservation of kinetic energy (since they collide elastically):

$\frac{1}{2}m_{1}v_{1_{i}}^{2} = \frac{1}{2}m_{1}v_{1_{f}}^{2} + \frac{1}{2}m_{2}v_{2_{f}}^{2}$

$m_{1}v_{1_{i}}^{2} = m_{1}v_{1_{f}}^{2} + m_{2}v_{2_{f}}^{2}$ (2)

By entering equation (1) into (2) we have:

$m_{1}v_{1_{i}}^{2} = m_{1}(v_{1_{i}} - \frac{m_{2}v_{2_{f}}}{m_{1}})^{2} + m_{2}v_{2_{f}}^{2}$

$0.1 kg*(6.20 m/s)^{2} = 0.1 kg*(6.2 m/s - \frac{0.3 kg*v_{2_{f}}}{0.1 kg})^{2} + 0.3 kg(v_{2_{f}})^{2}$

By solving the above equation for $v_{2_{f}}$ :

$v_{2_{f}} = 3.1 m/s$

Now, $v_{1_{f}}$ can be calculated with equation (1):

$v_{1_{f}} = 6.20 m/s - \frac{0.3 kg*3.1 m/s}{0.1 kg} = -3.1 m/s$

The minus sign of $v_{1_{f}}$ means that the ball 1 (100g) is moving in the negative x-direction after the collision.

Therefore, the magnitude of the velocities of the two balls after the collision is 3.1 m/s (each one).

I hope it helps you!

5 0

3 years ago

You walk 60m east and then 20m at 20 degrees south of west. What is your displacement?

stich3 [128]

Let north and east be posetive
Y=20sin20
=6.840402867 south
X=20cos20
18.79385243 west
Net horizontal components=60+(-18.79)
=41.20614758m
Net vertical=-6.84040267
X^2=41.20614758^2+(-6.684040267)^2
√x^2 =√1744.73771m
x=41.77m

5 0

3 years ago

Justine is ice-skating at the Lloyd Center. What is her final velocity if she accelerates at a rate of 2.0 m/s for 3.5 seconds?

belka [17]

Answer:

7 m/s

Explanation:

Acceleration, $a=\frac {v-u}{t}$

Where v and u are the final and initial velocities of the Justine respectively, t is the time taken for Justin to attain final velocity.

Making v the subject then

v=at+u

Taking u as zero then

Substituting 3.5 for t, 2 as a then

v=3.5*2=7 m/s

8 0

3 years ago

What is the unit of measurement for power?<br> A. m/s2<br> B. watts<br> C. joules<br> D. newtons

anyanavicka [17]

Power is the rate of doing work or using energy.

The unit of power is the watt.

1 watt = 1 joule per second

8 0

3 years ago