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bogdanovich [222]
3 years ago
14

Pls help i only have 2 minutes!!!!!!!!!!!!!!

Mathematics
2 answers:
nikdorinn [45]3 years ago
7 0

Answer:

(-25)+12

=13

40+(-63)

=23

umka21 [38]3 years ago
4 0

Answer:

40 + ( -63) is less

Step-by-step explanation:

.... .....

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A bridge hand is made up of 13 cards from a deck of 52. find the probability that a hand chosen at random contains at least 3 ki
Vlad [161]
1.
In total there are C(52, 13) ways that we can pick a hand, that is \frac{52!}{13!39!}


2.
P(a hand contains at least 3 kings)
                =P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

3.
first let's find P(a hand contains exactly 3 kings):

P(a hand contains exactly 3 kings)
              =n(a hand contains exactly 3 kings)/C(52, 13)
              
n(a hand contains exactly 3 kings)=C(4, 3)*C(48, 10)

where C(4,3) is the total number of ways we can pick 3 out of 4 kings,

C(48, 10) is the number of picking 10 letters to complete a hand, out of the 52-4=48 non-king cards.

so P(a hand contains exactly 3 kings)=[C(4, 3)*C(48, 10)]/C(52, 13)

4. with the same reasoning as in step 3:

P(a hand contains 4 kings)=n(a hand contains 4 kings)/C(52, 13)

                          = [C(4, 4)*C(48, 9]/C(52, 13)


5. 

P(a hand contains at least 3 kings)
                =P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

=[C(4, 3)*C(48, 10)]/C(52, 13)+ [C(4, 4)*C(48, 9)]/C(52, 13)

=\frac{C(4, 3)*C(48, 10)+C(4, 4)*C(48, 9)}{C(52, 13)}

=\frac{4* \frac{48!}{10!38!} + \frac{48!}{9!39!}}{ \frac{52!}{13!39!} }

simplify by 38! in the denominators and 48! in the numerators :

\frac{4* \frac{1}{10!} + \frac{1}{9!39}}{ \frac{52*51*50*49}{13!39} } 



now simplify by 9! in all denominators:

\frac{ \frac{4}{10}+  \frac{1}{39} }{ \frac{52*51*50*49}{13*12*11*10*39}}


\frac{ 0.426 }{ 9.7} =0.044

4 0
4 years ago
Which is the simplified rational expression for 9x-5/4x-1 + (3x+8/4x-1 - 5x+3/4x-1)
Morgarella [4.7K]

Step-by-step explanation:

\frac{9x - 5}{4x - 1}  + ( \frac{3x + 8}{4x - 1}  -  \frac{5x + 3}{4x - 1} ) \\  \\  =  \frac{9x - 5}{4x - 1}  + ( \frac{(3x + 8) - (5x + 3)}{4x - 1}) \\  \\ =  \frac{9x - 5}{4x - 1}  + ( \frac{3x + 8 - 5x  - 3}{4x - 1}) \\  \\  =  \frac{9x - 5}{4x - 1}  +  \frac{5 - 2x  }{4x - 1} \\  \\ =  \frac{9x - 5 + 5 - 2x}{4x - 1}  \\  \\  \red{ \boxed{  \therefore \:  \frac{9x - 5}{4x - 1}  + ( \frac{3x + 8}{4x - 1}  -  \frac{5x + 3}{4x - 1} )=  \purple{\frac{7x}{4x - 1} }}} \\

6 0
3 years ago
plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =
ElenaW [278]

Answer with Step-by-step explanation:

We are given that

f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}

\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}

Right hand limit =RHL when x> 2

Substitute

x=2+h

\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}

=\frac{2}{4}=\frac{1}{2}

LHL=RHL=\frac{1}{2}

f(2)=1

LHL=RHL\neq f(2)

Hence, function is discontinuous at x=2

4 0
4 years ago
Eliana drove her car 81 km, space, k, m and used 9 liters of fuel. She wants to know how many kilometers(x) she can drive on 22
olya-2409 [2.1K]

Question: Eliana drove her car 81 km, space, k, m and used 9 liters of fuel. She wants to know how many kilometers(x) she can drive on 22 liters of fuel. She assumes her car will continue consuming fuel at the same rate. How far can Eliana drive on 222222 liters of fuel?

Answer: Eliana can drive on 22 liters of fuel and can drive up to 198 km

Explanation: 9 liters = 81km so 81 divided by 9  so now it becomes 1 liter =9km  22 liters so 22x9 = 198km

question answered by

(jacemorris04)

8 0
3 years ago
Is 6xyz and 8xy like terms
Korolek [52]
You can combine variables that are the same such as 6x and 8x, and y and y. that would end up being 14x+2y+z
6 0
3 years ago
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