Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
8 tickets
Step-by-step explanation:
x = 10 in the given equation.
We have then:
C (x) = 17.5x - 10
C (10) = 17.5 * (10) - 10
C (10) = 165
Answer:
to buy 10 tickets cost:
$ 165
b. How many tickets can you buy with $ 130?
For this case we must make the substitution: C (x) = 130
We have then:
C (x) = 17.5x - 10
130 = 17.5x - 10
Clearing x we have:
17.5x = 130 + 10
17.5x = 140
x = (140) / (17.5)
x = 8
Answer:
You can buy 8 tickets with $ 130
Hello!
The least common multiple is 3
Hope this helps!
I think the answer to m is 8
