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Greeley [361]
3 years ago
6

t%7Bs%7D%20" id="TexFormula1" title="h(s) = 1 + \sqrt{s \ } \div 1 - \sqrt{s} " alt="h(s) = 1 + \sqrt{s \ } \div 1 - \sqrt{s} " align="absmiddle" class="latex-formula">
differentiate using quotient rule ​
Mathematics
1 answer:
ruslelena [56]3 years ago
6 0

Answer:

   h^{l} (s) = \frac{1 }{(\sqrt{s}) (1-\sqrt{s})^{2}  }

Step-by-step explanation:

<u><em>Explanation</em></u>

Given that

          h(s) = \frac{1+\sqrt{s} }{1-\sqrt{s} }

Differentiating equation (i) with respective to 'x'  ,we get

       h^{l} (s) =\frac{1-\sqrt{s}) \frac{1}{2\sqrt{s} } -(1+\sqrt{s})(\frac{-1}{2\sqrt{s} )}  }{(1-\sqrt{s})^{2}  }

      h^{l} (s) = \frac{\frac{1}{2\sqrt{s} } -\frac{1}{2\sqrt{s} }X\sqrt{s} + \frac{1}{2\sqrt{s} } +\frac{1}{2\sqrt{s} }X\sqrt{s} }{(1-\sqrt{s})^{2}  }

      h^{l} (s) = \frac{\frac{2}{2\sqrt{s} } }{(1-\sqrt{s})^{2}  }

     h^{l} (s) = \frac{1 }{(\sqrt{s}) (1-\sqrt{s})^{2}  }

 

     

       

         

       

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