v + m = 32 and v = 5 + 2m are the equations that are used to determine m, the number of stuffed animals Mariposa has
Number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
<h3>
<u>Solution:</u></h3>
Let "v" be the number of stuffed animals with Veronica
Let "m" be the number of stuffed animals with Mariposa
Given that,
Together, they have 32 stuffed animals
Therefore,
v + m = 32 --------- eqn 1
Veronica has 5 more than double the number of stutted animals as her friend Mariposa
Therefore,
Number of stuffed animals with Veronica = 5 + 2(number of stuffed animals with Mariposa)
v = 5 + 2m ---------- eqn 2
Thus eqn 1 and eqn 2 can be used to determine m, the number of stuffed animals Mariposa has
Let us solve eqn 1 and eqn 2
Substitute eqn 2 in eqn 1
5 + 2m + m = 32
5 + 3m = 32
3m = 32 - 5
3m = 27
<h3>m = 9</h3>
Substitute m = 9 in eqn 2
v = 5 + 2(9)
v = 5 + 18
<h3>v = 23</h3>
Thus number of stuffed animals Mariposa has is 9 and number of stuffed animals with Veronica is 23
Answer:
Step-by-step explanation:
![Volume\:of\:cube:V=a^{3} \:(a\:is\:the\:length\:of\:each\:edge)\\\Leftrightarrow a=\sqrt[3]{V} \Leftrightarrow a=\sqrt[3]{729} =9](https://tex.z-dn.net/?f=Volume%5C%3Aof%5C%3Acube%3AV%3Da%5E%7B3%7D%20%5C%3A%28a%5C%3Ais%5C%3Athe%5C%3Alength%5C%3Aof%5C%3Aeach%5C%3Aedge%29%5C%5C%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7BV%7D%20%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7B729%7D%20%3D9)
Answer:
This sequence is arithmetic, and the next term is 25
Step-by-step explanation:
The common difference of the sequence is 6, so the next term is 19+6=25.
The difference between the consecutive terms is constant => sequence is arithmetic.
<u>7-1=6</u>
<u>13-7=6</u>
<u>19-13=6</u>
Answer:
Step-by-step explanation:
There are
2 yellow
3 magenta
5 blue
marbles in the bag.
So total of 2 + 3 + 5 = 10 marbles
We have to multiply the probability of yellow on first pick by the probability of yellow on second pick (WITHOUT REPLACEMENT).
We denote P(Y1) as probability of yellow on first draw &
P(Y2) as probability of yellow on second draw
Thus,
P(Y1) = 2/10 = 1/5 [since 2 yellow and 10 total marbles]
Now,
P(Y2) = 1/9 [since now 1 yellow is taken out and NOT replaced, so we have 1 yellow remaining and total 9 marbles]
Now, we multiply:
P(Y1) * P(Y2) = 1/5 * 1/9 = 1/45
The probability is
