All categories

3 years ago

A(n) _______________ can be formed by linking together several monosaccharides via glycosidic bonds.

Chemistry

1 answer:

mario62 [17]3 years ago

7 0

Answer:

A polysaccharide (n) can be formed by linking several monosaccharides through glycosidic linkages.

Explanation:

Polysaccharides are carbohydrates or complex carbohydrates, where monosaccharides join with glucosidic bonds to form a more complex structure that would be the polysaccharide.

An example of a polysaccharide is starch, or glycogen.

Starch is found in many foods such as potatoes or rice, and glycogen is a form of energy reserve of our organism housed in muscles and liver to fulfill locomotion, physical activity, and other activities that consist of glycolysis.

Polysaccharides are degraded in our body by different stages, and several enzymes unlike monosoccharides or disaccharides, since they have more unions and a more complex structure to disarm in our body and thus assimilate it.

Polysaccharides are also part of animal structures, such as insect shells or nutritional sources, among others.

You might be interested in

Only animals and not plants can adapt to their environment true or false

Vladimir79 [104]

Answer:

true

Explanation:

np have a good day brainliest?

3 0

3 years ago

Why is photosynthesis an example of chemical change, and why is it classified as endothermic?

Alexeev081 [22]

Answer:

It is an example of chemical reaction because carbon dioxide and water are converted into glucose and oxygen. If that makes any sense. and it is classified as endothermic because it requires the input of energy in the form of solar energy.

Explanation:

3 0

3 years ago

How many liters of water do we need to add to 5.00 moles to get a 0.648 M solution?

Tanya [424]

Answer: This is a typical acid/base equilibrium problem, that involves the use of logarithms.

Explanation:We assume that both nitric acid and hydrochloric acid dissociate to give stoichiometric

Moles of nitric acid:

26.0

−

⋅

8.00

⋅

−

0.208

⋅

(

)

And, moles of hydrochloric acid:

88.0

−

⋅

5.00

⋅

−

0.440

⋅

(

)

This molar quantity is diluted to

1.00

. Concentration in moles/Litre =

(

0.208

0.440

)

⋅

0.648

⋅

−

Now we know that water undergoes autoprotolysis:

(

)

⇌

−

. This is another equilibrium reaction, and the ion product

[

]

[

−

]

. This constant,

−

298

[

]

0.648

⋅

−

;

[

−

]

[

]

−

0.648

−

log

[

]

−

log

(

0.648

)

Alternatively, we know further that

. Once you have

is easy to find. Take the antilogarithm of this to get

[

−

]

Answer link

4 0

2 years ago

An experiment shows that a 250 ?ml gas sample has a mass of 0.430 g at a pressure of 736 mmhg and a temperature of 28 ?c.

dmitriy555 [2]

What we're looking for here is the gas sample's molar mass given its mass, pressure, volume, and temperature. Recalling the gas law, we have

$PV = nRT$ or
$n = \frac{PV}{RT}$

where R is <span>0.08206 L atm / mol K, P is the given pressure, T is the temperature, and V is the volume.

Before applying the values given, it is important to make sure that they are to be converted to have consistent units with that of R.
</span>
Thus, we have

P = 736/ 729 = 0.968 atm
T = 28 + 273.15 = 301.15 K
V = 250/1000 = 0.250 L

Now, applying these converted values into the gas law, we have

$n = \frac{(0.968 atm)(0.250 L)}{(0.08206 L.atm/mol.K)(301.15 K)}$
$n = 0.00979 moles$

Given that the mass of the sample is 0.430 g, we have

$molar mass = \frac{mass}{number of moles}$
$molar mass = \frac{0.430}{0.00979} = 43.9$

Thus, the gas sample has a molar mass of 43.9 g/mol.

4 0

3 years ago

The combustion of 3.795 mg of liquid B, which contains only C, H, and O, with excess oxygen gave 9.708 mg of CO2 and 3.969 mg of

attashe74 [19]

Answer:

Explanation:

9.708 mg of CO₂ will contain 12 x 9.708 / 44 = 2.64 g of C .

3.969 mg of H₂O will contain 2 x 3.969 / 18 = .441 g of H .

mg of O in given liquid B = 3.795 - ( 2.64 + .441 ) = .714 mg

ratio of mg of C , H , O in the compound = 2.64 : .441 : .714

ratio of no of atoms of C , H , O in the compound

= 2.64 / 12 : .441 /1 : .714 / 16

= .22 : .44 : .0446

= .22 / .22 : .44 / .22 : .044 / .22

= 1 : 2 : .2

1 x 5 : 2 x 5 : .2 x 5

= 5 : 10 : 1

empirical formula of the compound = C₅H₁₀O

Volume of 89.8 mL at 1 .00 atm at 200⁰C

volume of gas at 1 atm and 0⁰C = 89.8 x 273 / 473 mL

= 51.83 mL

51.83 mL weighs .205 g

22400 mL will weigh .205 x 22400 / 51.83 g

= 88.6 g

So molecular weight = 88.6

Let molecular formula be (C₅H₁₀O)ₙ

molecular weight = n ( 5 x 12 + 10 + 16 )

= 86 n

86 n = 88.6

n = 1 approx

So molecular formula is same as empirical formula

C₅H₁₀O is molecular formula .

6 0

3 years ago