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ryzh [129]
3 years ago
14

Question 4

Chemistry
1 answer:
pickupchik [31]3 years ago
5 0
The answer is
3. Neutrons
I hope that helped. Good Luck!
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What is the molarity of HCl if 34.81 mL of a solution of HCl contain 0.3297 g of HCl?
Temka [501]

Answer:

0.2598 M

Explanation:

Molarity is mol/L, so we have to convert the grams to moles and the mL to L. To convert between grams and moles you need the molar mass of the compound, which is 36.46g/mol.

0.3297gHCl*\frac{1molHCl}{36.46gHCL} = 0.00904279 mol HCl

34.81 mLHCl * \frac{1L}{1000L} = 0.03481 L HCl

\frac{0.00904279molHCl}{0.03481 L HCl} = 0.25977554 mol/L

Round to the lowest number of significant figures = 0.2598 M

6 0
3 years ago
In a ______, substance have no definitie volume and particles move very quickly
kow [346]
Gas is the correct answer
7 0
3 years ago
What is the name of the following compound? A line-angle formula shows a ring with six vertices and a circle inscribed. A Cl ato
ozzi

Answer: Option C. p-dichlorobenzene and 1,4-dichlorobenzene.

Explanation:

A line-angle formula with six vertices and a circle inscribed corresponds to the compound known as benzene.

Further, according to the IUPAC standards for naming benzene derivatives, you must first number the position of the substituent. In this case, the substituents (chloros) are located at the positions 1 and 4; also, for the benzene derivatives when they have 2 substituents and the positions are 1 and 4, this configuration is known as <em>para </em>or <em>p </em>configuration.

Additionally, this compound has 2 substituents (chloros) so you have to indicate this number (di).

Therefore, the correct answer is C. p-dichlorobenzene and 1,4-dichlorobenzene.

4 0
3 years ago
One example of an ionic compound is<br><br> F2 <br> CO2<br> HBr<br> MgCL2
allochka39001 [22]
MgCl2 because it is the only option in which a metal appears with a nonmetal. In this case, the metal transfers electrons to the nonmental because the metal has a lower ionization energy.
7 0
3 years ago
Read 2 more answers
replacing standard incandescent lightbulbs with energy-efficient compact fluorescent lightbulbs can save a lot of energy. Calcul
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The difference between the wattage is 60-18=42W. The saving in energy over 10 hrs is 10×42=420 watt-hours=0.42kWh
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2 years ago
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