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Anni [7]
3 years ago
5

Solve 5 |x + 3| – 12 < 13.

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

x<2 and x> -8

Step-by-step explanation:

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Frank and his family went on vacation one summer, and drove 3,000 miles in 10 days. If they drove an equal distance every day, h
kiruha [24]

Answer:

Distance cover by Frank and family each day = 300 miles per day

Step-by-step explanation:

Given:

Total distance cover by Frank and family = 3,000 miles

Number of days = 10

Find:

Distance cover by Frank and family each day

Computation:

Distance cover by Frank and family each day = Total distance cover by Frank and family / Number of days

Distance cover by Frank and family each day = 3,000 / 10

Distance cover by Frank and family each day = 300 miles per day

3 0
3 years ago
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Simplify:
miv72 [106K]

576 =  {2}^{6}  \times  {3}^{2}  \\  \\
64 =  {2}^{6}






good luck
6 0
3 years ago
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Please helpp meeee!!!
Law Incorporation [45]

Answer:

im pretty sure the answer would be,

2 \frac{1}{2}

Step-by-step explanation:

the median is the middle number of the data, and since there are two medians, you find the mean of the two numbers by adding them together, and then you divide it by 2.

5 0
3 years ago
Some helppppp!!!!! I’m having trouble
USPshnik [31]
Answer:

1.4*40=56cm, DVD’s he has

1.4*3=4.2cm

56+4.2=60.2cm, whoops too much. So instead 1.4*2= 2.8cm, 56+2.8=58.8cm Is Your Answer.
3 0
3 years ago
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Find an equation of the plane with x-intercept a, y-intercept b, and z-intercept c. What is the distance between the origin and
Elenna [48]

Answer:

The equation is:

(1/a)x + (1/b)y + (1/c)z = 1

Step-by-step explanation:

The direction vector between the points (a, 0, 0) and (0, b, 0) is given as:

<0 - a, b - 0, 0 - 0>

<-a, b, 0> .....................(1)

The direction vector between (0, 0, c) and (0, b, 0) is given as:

<0 - 0, b - 0, 0 - c>

= <0, b, -c> .....................(2)

To obtain the direction vector that is normal to the surface of the plane, we take the cross product of (1) and (2).

Doing this, we have:

<-a, b, 0> × <0, b, -c> = <-bc, -ac, -ab>

To find the scalar equation of the plane we can use any of the points that we know. Using (0, b, 0), we have:

(-bc)x + (-ac)y + (-ab)z = (-bc)0 + (-ac)b + (-ab)0

(bc)x + (ac)y + (ab)z = (ac)b

Dividing both sides by abc, we have:

(1/a)x + (1/b)y + (1/c)z = 1

3 0
3 years ago
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