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3 years ago

Is the following a geometric sequence? 1,2,3,4,5....

2 answers:

7 0

Nope, this isn’t a geometric sequence. A geometric sequence is a sequence in which each previous number is multiplied by a fixed number each time.

AysviL [449]3 years ago

4 0

Answer:

Step-by-step explanation:

No this is increasing by 1 each time and therefore it's an arithmatic sequence

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A recipe requires 1/5 cup of milk for each 1/4 cup of water. How many cups of water are needed for each cup of milk?

Lelechka [254]

Answer:

1 1/4

Step-by-step explanation:

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3 years ago

A second bag of 40 marbles contains 11 red marbles, 9 blue marbles and 20 green marbles.

Goryan [66]

Answer:

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3 years ago

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How to solve 9 * 4 - 8 / 2 *4

egoroff_w [7]

Answer: the answer is 20

Step-by-step explanation:

Use order of operations and divide 8 by 2 and you get 4. Then use the PEMDAS (parentheses,exponents,multiplacation,division,addition, subtraction) method. Go left to right. And solve. :) I hope this helps

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3 years ago

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Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .