Are you looking for the length from E to F?
You have 50 ways because if there are 10 different types of prizes with 5 prizes you can just multiply that to get your different ways to select the prizes.
Since you're working with the ASA postulate, you're looking to show congruence of the angles at either end of a side. You're given side AC and angle A as congruent with their counterparts. Obviously, you also need to show congruence of angle C with its counterpart, angle Z.
selection B is appropriate
Answer:
the last one
Step-by-step explanation:
Answer:
we conclude that:
Step-by-step explanation:
Given
f(x) = x+9
g(x) = x² + 7x – 14
To determine
g(f(-5)) = ?
First, we need to find f(-5)
f(x) = x+9
substitute x = -5
f(-5) = (-5)+9
f(-5) = -5+9
f(-5) = 4
so
g(f(-5)) = g(4)
Now, we need to find g(4)
g(x) = x² + 7x – 14
substitute x = 4
g(4) = (4)² + 7(4) - 14
g(4) = 16 + 28 - 14
g(4) = 30
i.e.
g(f(-5)) = g(4) = 30
Therefore, we conclude that:
