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Zarrin [17]
3 years ago
5

Calculate the volume of 38.0 g of carbon dioxide at STP. Enter your answer in the box provided. L

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

19.3 L

Explanation:

V= n × 22.4

where V is volume and n is moles

First, to find the moles of CO2, divide 38.0 by the molecular weight of CO2 which is 44.01

n= m/ MM

n= 38/ 44.01

n= 0.86344012724

V= 0.86344012724 × 22.4

V= 19.3410588502 L

V= 19.3 L

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If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

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3 years ago
Write the balanced chemical equation where liquid decane burns in oxygen gas to form carbon dioxide gas and water vapor. Use the
Allushta [10]

Answer:

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Explanation:

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From the question, one can work out which states of matter to assign to which species. The trick with organic equations of this nature is to try to balance everything but oxygen first. Make sure you balance oxygen last because it is the easiest to balance.

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Explanation:

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In emerging economies, the use of technology is still more common among the young and the educated

A farmer takes a selfie with a smartphone at a rally in Jaipur, India. (Vishal Bhatnagar/AFP/Getty Images)

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