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azamat
3 years ago
10

How can mechanical waves help in the treatment of cancer?

Physics
2 answers:
Veronika [31]3 years ago
6 0

Beams of X-rays are targeted at a cancerous tumor from outside the body

Explanation:

Mechanical waves helps to treat cancer when beams of x-rays are targeted at a cancerous tumor from outside the body. These beams are energetic and ionizing. This will cause severe destruction of the cancerous cell.

  • In cancer therapy, ionizing radiations are used to destroy cancerous cells in living organisms.
  • Controlled doses of some forms of radiations are particularly known good medical procedures for curing cancer.
  • Other options are not ways in which mechanical waves helps to treat cancer.

learn more:

Lung cancer brainly.com/question/2533779

#learnwithBrainly

Aleks04 [339]3 years ago
4 0

Answer:

The answer would be D

Explanation:

Just did it on ed

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A sliver cylindrical rod has a length of 0.5 m and a radius of 0.4 m, find the density of the rod if it's mass is 2.640 kg
Serga [27]

Answer:

Density=10.50kg/m³

Explanation:

Solution,\\Height(h)=0.5m\\Radius(r)=0.4m\\Now, \\Volume=\pi r^{2} h\\\\Volume=\pi *(0.4m)^{2} *0.5m\\\\Volume=0.251327m^{3} \\\\Again,\\\\Density=\frac{mass}{volume} \\\\Density=\frac{2.640kg}{0.251327} \\\\Density=10.50kg/m^{3}

7 0
2 years ago
What does every element found in group 3 have in common? Choose the best answer(s). *
Serggg [28]

Answer:

THE 2ND ONE HOPE THIS HELPED GOD BLESS U

Explanation:

4 0
3 years ago
5. __________ is the idea that all people must follow the law and that the law is applied to all equally even people in the gove
padilas [110]
The answer is Rule of the law
5 0
2 years ago
If a builder of mass 75kg climbs a vertical ladder of 25m how much energy has she gained ?
erica [24]
So,

GPE (graviational potential energy) = mass x g x height

GPE is depends on where zero height is defined.  In this situation, we define h = 0 as the initial height.

GPE = 75 \ kg*9.8 \ \frac{m}{s^2}*25 \ m

GPE = 18,375 \frac{kg*m^2}{s^2}

GPE = 18,375 \ joules(J) \ or \ 18.375 \ kilojoules(kJ)

The builder has gained 18.375 kJ of PE.
4 0
2 years ago
How do you do this question?
umka2103 [35]

Explanation:

The moment of inertia of each disk is:

Idisk = 1/2 MR²

Using parallel axis theorem, the moment of inertia of each rod is:

Irod = 1/2 mr² + m (R − r)²

The total moment of inertia is:

I = 2Idisk + 5Irod

I = 2 (1/2 MR²) + 5 [1/2 mr² + m (R − r)²]

I = MR² + 5/2 mr² + 5m (R − r)²

Plugging in values:

I = (125 g) (5 cm)² + 5/2 (250 g) (1 cm)² + 5 (250 g) (5 cm − 1 cm)²

I = 23,750 g cm²

7 0
3 years ago
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